Question

在SQL Server中进行选择时，我可以在查询文本的开头或结尾添加％以表示我想要其他文本的任意数量的字符，但我不知道如何在中间执行此操作。

e.g。我想要SQL如下，

select *
From Table
Where name like '%[Error] Something failed in (%) session%'

当遇到以下数据时

Row | Date      | Log Message
1   |2016-01-01 |'[Error] Something failed in (Freds) session'
2   |2016-01-01 |'[Error] Something failed in (Ilenes) session'
3   |2016-01-01 |'[Error] Something failed in (Freds) session'; Some other warning
4   |2016-01-01 |'[Warning] Something else went wrong'
5   |2016-01-01 |'[Warning] Some other warning'

会给我

Row |Date       | Log Message
1   |2016-01-01 |'[Error] Something failed in (Freds) session'
2   |2016-01-01 |'[Error] Something failed in (Ilenes) session'
3   |2016-01-01 |'[Error] Something failed in (Freds) session'; Some other warning

但相反，它什么都没有回来，我需要改变什么。

Answer 1

问题是由于字符串中存在[]。 []与LIKE运算符一起用于查找

指定范围内的任何单个字符（[a-f]）或设置（[abcdef]）中。

所以你需要ESCAPE 方括号

select 1 
where '[Error] Something failed in (Freds) session'
like '%\[Error] Something failed in (%) session%' escape '\'

或

select 1 
where '[Error] Something failed in (Freds) session'
like '%[[]Error] Something failed in (%) session%'

SQL FIDDLE DEMO

如何在sql server中间使用通配符，如查询

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