Question

使用库推送器ajax php发送一些参数时遇到问题。

它让我失望：SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data

代码PHP和JS：

<script src="https://js.pusher.com/3.0/pusher.min.js"></script>

<?php $this->load->view('scripts_ini'); ?>

<!-- inline scripts related to this page -->
<script type="text/javascript">

    var pusher = new Pusher('9999999999999999');
    var channel1 = pusher.subscribe('puntaje_channel1');

    channel1.bind('msg_puntaje1', function(rpta) {
        console.log('+>'+rpta);
        $('#sp_puntaje1').html(rpta);       
    });


    $(document).ready(function() {

        $('.puntaje1').click(function(e) {
            e.preventDefault();

            var puntaje1 = parseInt($('#sp_puntaje1').text());          

            $.ajax({
                url: 'push_puntaje1.php',
                type: "POST",
                dataType: "json",
                data : {
                    message: val_res,
                    socket_id: pusher.connection.socket_id
                }
            }).done(function(rpta) {
                console.log('->'+rpta);
                $('#sp_puntaje1').html(rpta);
            }).fail(function( jqXHR, textStatus, errorThrown){
                console.log('error, '+errorThrown);     
            });


        });

    }); 
</script>

代码PHP：

<?php
require 'Pusher.php';

$mensaje1 = $_POST['message'];

$pusher1 = PusherInstance::get_pusher();

$pusher1->trigger(
    'puntaje_channel1',
    'msg_puntaje1',
    $mensaje1,
    $_POST['socket_id']
);

echo $mensaje1;
?>

错误firefox：

POST http://localhost:8005/sportipd/page/push_puntaje1.php


messaje=3&socket_id=154278.1632118

error, SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data

我希望你能解决我的问题。

Answer 1

您收到json解析错误是因为没有发送override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) { var indexpath : NSIndexPath = self.tableView.indexPathForSelectedRow! var destViewController = segue.destinationViewController as! SecondView let row: Int = indexpath.row getMore(row) destViewController.nameString = namesArray[row] destViewController.companyString = companyArray[row] destViewController.homeNumber = homeNumber[row] destViewController.workNumber = workNumber[row] destViewController.mobileNumber = mobileNumber[row] destViewController.emailAddress = self.email dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0)) { if let url = NSURL(string: self.largeImageURL) { if let data = NSData(contentsOfURL: url) { dispatch_async(dispatch_get_main_queue()) { destViewController.pic = UIImage(data: data) } } } } destViewController.birthday = birthDate[row] destViewController.address = self.street + self.city + self.state + self.country + self.zip }，您正在发送json。

将此行text/html更改为：

echo $mensaje1;

您也可以将echo json_encode($mensaje1);标头设置为json，以确保它在您的PHP代码中如此读取：

Content-Type

使用ajax conpusher PHP错误JSON.parse？

1 个答案: