Question

您好我已经创建了干净的网址但我希望获得动态网址并获得动态查询

我想要链接像这样 http://localhost:8081/olshop/products/param/[category]-[gender]

     http://localhost:8081/olshop/products/param/[category]
   sample : http://localhost:8081/olshop/products/param/pants
   with paging
    http://localhost:8081/olshop/products/param/[category]/paging
    sample : http://localhost:8081/olshop/products/param/pants/1

 or 
     http://localhost:8081/olshop/products/param/[gender]
   sample : http://localhost:8081/olshop/products/param/m
   with paging
    http://localhost:8081/olshop/products/param/[gender]/paging
    sample : http://localhost:8081/olshop/products/param/m/1

or 
    http://localhost:8081/olshop/products/param/[gender]-[category]
   sample : http://localhost:8081/olshop/products/param/m-pants
   with paging
    http://localhost:8081/olshop/products/param/[gender]-[category]/paging
    sample : http://localhost:8081/olshop/products/param/m-pants/1

但是此用户可以像这样更改过滤器

<IfModule mod_rewrite.c>
    RewriteEngine On
    RewriteRule index$                                          index.php [L]
    RewriteRule ^products/(\d+)$                                index.php?p=products&page=$1 [L]
    RewriteRule ^products/param/([^/]+)/?$                      index.php?p=products&param=$1 [L]
    RewriteRule ^products/param/(.*)\/(\d+)$                    index.php?p=products&param=$1&page=$2 [L]
    RewriteRule ^([^/.]+)/?$                                    index.php?p=$1  [QSA,L]
</IfModule>

如何像这样的技术？

我对我的代码和.htaccess

的实现感到困惑

这是我目前的.htaccess

<?php 
         if($_GET['param']!=NULL)
         {
            $query = mysqli_query($con,"select *  from goods where category='".$_GET['param']."'  and gender='".$_GET['param']."' order by  date_publish DESC LIMIT $start, $limit");
         }
         else
         {
            $query = mysqli_query($con,"select *  from goods order by  date_publish DESC LIMIT $start, $limit");
         }
    ?>

这是我的代码

CMD

帮我谢谢

或者您有解决方案或其他？

Answer 1

您遇到的问题是您需要确定用户是否要求提供性别，类别或两者。因为你的性别是通用的和有限的; m = male，f = female，a = all例如，它们都是一个字符长，你最好只解析那些参数并查询页面是否存在。

您在这里遇到的唯一真正问题是您的性别/类别位置可以更改或反转，这意味着如果两者都提供，那么您需要查询这两种类型的两个部分，如果需要，那么您可以使用以下两个模式匹配以获取性别和类别，或者如果您决定使用其中一种格式，那么只需使用其中一种格式。

$param = 'pants-m'; //$_GET['param'];

if(preg_match('/^([m|f])(?:[-](.*))?$/i', $param, $match)) {
    $gender = $match[1];
    $category = isset($match[2]) ? $match[2] : null;
}
elseif(preg_match('/^([a-z0-9]{2,})(?:[-]([m|f]))?$/i', $param, $match)) {
    $gender = isset($match[2]) ? $match[2] : null;
    $category = $match[1];
}

var_dump($gender, $category);

如何实现动态url并获取动态查询

1 个答案: