从方法中确定定义类

Question

以下Python 3.5代码：

My type is <class '__main__.Derived'>
My type is <class '__main__.Derived'>

打印：

__init__()

我想知道，在每个My type is <class '__main__.Base'> My type is <class '__main__.Derived'> 内，定义方法的类，而不是派生类。所以我会得到以下印刷品：

 +- [2] fork https://github.com/Microsoft/opencv

      +- [3] branch https://github.com/Microsoft/opencv/tree/vs2015-samples

Answer 1

解决方案1 ​​

使用super().__thisclass__：

class Base(object):
    def __init__(self):
        print("My type is", super().__thisclass__)

class Derived(Base):
    def __init__(self):
        super().__init__()
        print("My type is", super().__thisclass__)

d = Derived()

My type is <class '__main__.Base'>
My type is <class '__main__.Derived'>

解决方案2

这个课程不那么优雅但硬连线：

class Base(object):
    def __init__(self):
        print("My type is", Base)

class Derived(Base):
    def __init__(self):
        super().__init__()
        print("My type is", Derived)

d = Derived()

输出：

My type is <class '__main__.Base'>
My type is <class '__main__.Derived'>