现在我有了这个:
[STAThread]
static void Main()
{
if (flag) //client view
Application.Run(new Main_Menu());
else
{
Application.Run(new ServerForm());
}
}
ServerForm.cs
public partial class ServerForm : Form
{
public ServerForm()
{
InitializeComponent();
BeginListening(logBox);
}
public void addLog(string msg)
{
this.logBox.Items.Add(msg);
}
private void button1_Click(object sender, EventArgs e)
{
}
private async void BeginListening(ListBox lv)
{
Server s = new Server(lv);
s.Start();
}
}
Server.cs
public class Server
{
ManualResetEvent allDone = new ManualResetEvent(false);
ListBox logs;
///
///
/// Starts a server that listens to connections
///
public Server(ListBox lb)
{
logs = lb;
}
public void Start()
{
Socket listener = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
listener.Bind(new IPEndPoint(IPAddress.Loopback, 1440));
while (true)
{
Console.Out.WriteLine("Waiting for connection...");
allDone.Reset();
listener.Listen(100);
listener.BeginAccept(Accept, listener);
allDone.WaitOne(); //halts this thread
}
}
//other methods like Send, Receive etc.
}
我想运行我的ServerForm
(它有ListBox来打印来自Server
的消息)。我知道ListBox
参数不起作用,但我无法在没有暂停Server
的情况下运行ServerForm
无限循环(我甚至无法移动窗口)。我也尝试使用Threads - 不幸的是它不起作用。
答案 0 :(得分:2)
WinForms有一个叫做UI线程的东西。它是一个负责绘制和处理UI的线程。如果该线程忙于做某事,UI将停止响应。
常规套接字方法是阻塞的。这意味着除非套接字上发生了某些事情,否则它们不会将控制权返回给您的应用程序。因此,每次在UI线程上执行套接字操作时,UI都将停止响应,直到套接字方法完成。
要解决这个问题,您需要为套接字操作创建一个单独的线程。
new ByteBuddy()
.subclass(Object.class)
.defineField("foo", Void.class)
.annotateField(annotationDescription)
.make();
但是,所有UI操作必须在UI线程上进行。这样,如果您尝试从套接字线程更新public class Server
{
ManualResetEvent allDone = new ManualResetEvent(false);
Thread _socketThread;
ListBox logs;
public Server(ListBox lb)
{
logs = lb;
}
public void Start()
{
_socketThread = new Thread(SocketThreadFunc);
_socketThread.Start();
}
public void SocketThreadFunc(object state)
{
Socket listener = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
listener.Bind(new IPEndPoint(IPAddress.Loopback, 1440));
while (true)
{
Console.Out.WriteLine("Waiting for connection...");
allDone.Reset();
listener.Listen(100);
listener.BeginAccept(Accept, listener);
allDone.WaitOne(); //halts this thread
}
}
//other methods like Send, Receive etc.
}
,您将获得异常。
解决这个问题的最简单方法是使用Invoke。