在我的服务器端，我设置了一个线程代码，每次客户端连接时都会创建一个新的Socket对象。然后我传递从客户端得到的任何东西以及连接到数据包处理程序的套接字并在那里进行计算。在我的主要表单中，我有一个listview，我通过实体框架填充，每当来自注册计算机的数据包连接时，我更新listview。所以我的问题是，当我更新它时，我可以从包处理程序类将套接字对象传递给listview的tag属性吗？
我的服务器端代码：
private void ReceivedCallback(IAsyncResult result)
{
Socket clientSocket = result.AsyncState as Socket;
SocketError ER;
try
{
int bufferSize = clientSocket.EndReceive(result, out ER);
if (ER == SocketError.Success)
{
byte[] packet = new byte[bufferSize];
Array.Copy(_buffer, packet, packet.Length);
Console.WriteLine("Handling packet from IP:" + clientSocket.RemoteEndPoint.ToString());
//Handle packet stuff here.
PacketHandler.Handle(packet, clientSocket);
_buffer = new byte[61144];
clientSocket.BeginReceive(_buffer, 0, _buffer.Length, SocketFlags.None, ReceivedCallback, clientSocket);
//clientSocket.BeginReceive(new byte[] { 0 }, 0, 0, 0, ReceivedCallback, clientSocket);
}
else
{
Console.WriteLine("No bytes received, we're closing the connection.");
clientSocket.Close();
}
}catch(SocketException ex)
{
Console.WriteLine("We caught a socket exception:" + ex.Message);
clientSocket.Close();
}
}
我的包处理程序类：
public static void Handle(byte[] packet, Socket clientSocket)
{
if (clientSocket.Connected)
{
if (packet.Length > 0)
{
IPEndPoint RemoteIP = (IPEndPoint)clientSocket.RemoteEndPoint;
ushort packetLength = BitConverter.ToUInt16(packet, 0);
ushort packetType = BitConverter.ToUInt16(packet, 2);
ushort packetID = BitConverter.ToUInt16(packet, 4);
Console.WriteLine("We received a packet of Type: {0}, ID: {1} FROM {2}", packetType, packetID, RemoteIP.ToString());
if (packetType == 1)
{
switch (packetID)
{
case 1://Check if computer is registered in the database
CheckRegisteredRequest request1 = new CheckRegisteredRequest(packet);
Console.WriteLine("We received (Case 1): " + request1.Text);
string Response = "";
bool found = false;
ServerDbContext database = new ServerDbContext();
foreach (computers pcs in database.computers)
{
if (pcs.name == request1.Text.Split(',')[0])
{
found = true;
if (pcs.computer_ip == request1.Text.Split(',')[1])
{
//We found a computer with that name and ip address
Response = "true";
CheckRegisteredResponse resp1 = new CheckRegisteredResponse(Response);
clientSocket.Send(resp1.Data);
computers registeredPC;
var name = request1.Text.Split(',')[0];
using (var ctx = new ServerDbContext())
{
registeredPC = ctx.computers.Where(c => c.name == name).FirstOrDefault<computers>();
}
if (registeredPC != null)
{
registeredPC.networkStatus = "online";
}
using (var ctx = new ServerDbContext())
{
ctx.Entry(registeredPC).State = System.Data.Entity.EntityState.Modified;
ctx.SaveChanges();
}
addNewLog("Computer: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1]);
RaiseFeedback("PC: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1]);
break;
}
else
{
//We found a computer with that name but a different ip address, update it
var name = request1.Text.Split(',')[0];
var registeredPC = new computers();
using (var ctx = new ServerDbContext())
{
registeredPC = ctx.computers.Where(c => c.name == name).FirstOrDefault<computers>();
}
if (registeredPC != null)
{
var ip = request1.Text.Split(',')[1];
registeredPC.computer_ip = ip;
registeredPC.networkStatus = "online";
}
using (var ctx = new ServerDbContext())
{
ctx.Entry(registeredPC).State = System.Data.Entity.EntityState.Modified;
ctx.SaveChanges();
}
Response = "true";
CheckRegisteredResponse resp1 = new CheckRegisteredResponse(Response);
clientSocket.Send(resp1.Data);
addNewLog("Computer: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1]);
RaiseFeedback("PC: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1]);
break;
}
}
}
if (!found)
{
//There is no computer with that name in the database so send false
Response = "false";
CheckRegisteredResponse resp1 = new CheckRegisteredResponse(Response);
clientSocket.Send(resp1.Data);
}
break;... and so on....
所以我尝试通过处理程序：
这是我的自定义事件处理程序Args：
public class TextArgs : EventArgs
{
#region Fields
private string szMessage;
private Socket _sockets123;
#endregion Fields
#region ConstructorsH
public TextArgs(string TextMessage,Socket sock)
{
if (sock != null)
{
_sockets123 = sock;
szMessage = TextMessage;
}
else
{
szMessage = TextMessage;
}
}
#endregion Constructors
#region Properties
public string Message
{
get { return szMessage; }
set { szMessage = value; }
}
public Socket _socket
{
get { return _sockets123; }
set { _sockets123 = value; }
}
#endregion Properties
}
这是我在PacketHandler类中定义该处理程序的方式： 公共静态事件LogsEventHandler反馈;
private static void RaiseFeedback(string p, Socket sock)
{
LogsEventHandler handler = Feedback;
if (handler != null)
{
handler(null,new TextArgs(p,sock));
}
}
每当计算机注册或连接时，我都会执行以下操作：
RaiseFeedback("PC: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1], clientSocket);
或
RaiseFeedback("PC: " + request1.Text.Split(',')[0] + " came online - IP: " + request1.Text.Split(',')[1], null);
事件以我的主要形式触发了这两种方法：
private void OnFeedbackReceived(object sender, TextArgs e)
{
Invoke((MethodInvoker)delegate
{
UpdateComputers();
UpdateGUI(e.Message,e._socket);
}
);
}
public void UpdateGUI(string s, Socket sock)
{
LogBox.Text += s;
LogBox.AppendText(Environment.NewLine);
using (var context = new ServerDbContext())
{
var PCInfo = context.viewUsersInfo;
dataGridView1.DataSource = PCInfo.ToList();
}
if (sock != null)
{
ListViewItem item = ComputersList.FindItemWithText(s.Split(':')[1].ToString());
item.Tag = sock;
}
}
答案 0 :(得分：1)
问题：是的，你可以。 Control.Tag属于object类型，可以容纳您选择的任何内容。
所以你可以写
Socket socket = someSocket;
ListViewItem item = listView1.FindItemWithText(someText);
if (item != null) item.Tag = socket; else Console.WriteLine(someText + " not found!);
并将其检索为：
if (item.Tag != null) someSocket = item.Tag AS socket;
if (someSocket != null) ..
在检索时，你应该注意演员的成功，但是如果Socket仍然存在并且很好......
问题：代码中的堆栈溢出是由于一个错误的，短路的属性，你现在已经修复了。一般来说，如果他们实际上做的不仅仅是gettin和设置，你只需要编写显式的getter和setter。
他们可以注销测试数据，更新其他属性，依赖属性，进行检查或转换或执行其他操作。
但如果不需要它，只需创建私有字段并编写自动getter和setter：
public Socket MySocket {get; set;}
另请注意，naming convention会要求您capitalize名称！