Question

从wp-config.php文件中我需要获取数据库名称，用户名和密码值，而不包括wp-config文件，并将它们分配给三个单独的变量以供进一步使用。

define('DB_NAME', 'somedb');
define('DB_USER', 'someuser');
define('DB_PASSWORD', 'somepass');

我的脚本将在同一个文件夹中。不，我不想使用任何WordPress功能。

Answer 1

如果您确实不想包含该文件，请在评论中提及，
我们可以使用file()将文件内容读入数组。

迭代每一行并应用一些清理，直到我们得到一种我们可以使用的格式：

<?php

$config = file('wp-config.php');

$dbLines = [];

foreach($config as $line){
    if (stristr($line,"define('DB_")!==FALSE){
        $dbLines[] = $line;
    }
}

array_walk($dbLines, 'cleanup'); 
// apply the cleanup() function to all members of the array, basically to each line

function cleanup(&$value){
    // replace the leading 'define(' and trailing closing bracket
    $value = str_replace(
        array("define(",");"),'',$value
        );
    $value = preg_replace('#\s+//(.*)#','',$value); // remove the comments
}

// at this point we have a csv structure with a single quote as the delimiter
// comma+space as a separator

$dbConfig = [];

foreach ($dbLines as $dbline){
    // read the line into separate variables and build an array
    list($key,$value) = (str_getcsv($dbline,', ',"'"));
    $dbConfig[$key] = $value;
}

print_r($dbConfig);

这将输出

Array
(
    [DB_NAME] => putyourdbnamehere
    [DB_USER] => usernamehere
    [DB_PASSWORD] => yourpasswordhere
    [DB_HOST] => localhost
    [DB_CHARSET] => utf8
    [DB_COLLATE] =>
)

如果要从数组中访问单个元素，只需

print $dbConfig['DB_HOST'];

如何从PHP文件中获取一段文本

1 个答案: