我有两张桌子
NoRoom varchar(50) primary key,
kindRoom nvarchar(50),
price float,
priceCurrent float,
R_status nvarchar(50),
nametour nvarchar(50),
checkIn date,
checkOut date,
company nvarchar(50),
idRoom nvarchar(50) foreign key references Rooms(NoRoom)
这是我的代码
SELECT rooms.noroom,
rooms.kindroom,
Count(checkintour.idroom) AS numberoforder
FROM rooms
LEFT JOIN checkintour
ON( rooms.noroom = checkintour.idroom )
GROUP BY rooms.noroom,
rooms.kindroom
ORDER BY numberoforder DESC
输出就像这样
+-----------+----------+----------------+
| No Room | KindRoom | NumberOfOrder |
+-----------+----------+----------------+
| PO0051 VIP 1
| PO0053 Single 1
| PO0054 VIP 1
| PO0055 VIP 1
| PO0056 VIP 1
| PO0057 VIp 1
| PO0058 VIP 1
| PO0059 VIP .
| PO0060 . ..
| PO0061 .. ...
| PO0062
| | |
| | | |
| | | |
+-----------+----------+----------------+
如何获得最大NumberOfOrder? 换句话说,如果房间的类型是VIP我想要总结那个房间的所有订单数量
答案 0 :(得分:0)
IIllegalException
答案 1 :(得分:0)
好的我找到了
select Rooms.kindRoom,
COUNT(CheckInTour.idRoom) as numberoforder
from Rooms
left join CheckInTour
on(Rooms.NoRoom = CheckInTour.idRoom)
group by
Rooms.kindRoom
order by numberoforder desc