Question

我有这个xml Feed ...

$xml=simplexml_load_file("../feed/feed") or die("Error: Cannot create object");
$partener = 'toys';

foreach($xml -> product as $row) {
    $magazin = $partener;
    $titlu = $row -> title;
    $descriere = $row -> description;
    $pret = $row -> price;
    $imagine1 = $row -> images1;
    $imagine2 = $row -> images2;

    $sql = "INSERT INTO toys (magazin,titlu,descriere,pret,imagine1,imagine2)
            VALUES ('$magazin','$titlu','$descriere','$pret','$imagine1','$imagine2') ";
        mysqli_query($conn, $sql);
}

......这部分剧本......

{{1}}

...结果是：导入了标题，描述和价格，但无法导入image1和images2。为什么？我是初学者。拜托，有人可以帮帮我吗？

Answer 1

这两张照片不是产品的子女，而是其孙子。只需将父images->添加到路径中即可获取其值：

foreach($xml -> product as $row) {
    $magazin = $partener;
    $titlu = $row -> title;
    $descriere = $row -> description;
    $pret = $row -> price;

    $imagine1 = $row->images->image1;
    $imagine2 = $row->images->image2;

    $sql = "INSERT INTO toys (magazin,titlu,descriere,pret,imagine1,imagine2)
            VALUES ('$magazin','$titlu','$descriere','$pret','$imagine1','$imagine2') ";
    mysqli_query($conn, $sql);
}

如何导入包含多个图像的XML Feed

1 个答案: