Question

你好我试图计算每个员工的工资行数。

我有前两张桌子。

表员工

id_____________name

1..............sam

2..............greg

3..............vic

4..............steve

表薪水

id____________salary

1.............10000

1.............15000

2.............30000

3.............13000

4.............90000

4.............20000

我需要的结果是

id| name | salary| count

1 | sam  | 10000 | 2

1 | sam  | 15000 | 2

2 | greg | 30000 | 1

3 | vic  | 13000 | 1

4 |steve | 90000 | 2

4 |steve | 90000 | 2

总结：我有4名员工过去的工资。我试图创建一个查询，显示工资列表和员工有多少工资。

这是我尝试的但是我得到6来计算...

create temporary table rates
SELECT e.id, e.name, s.salary, count(*) as count
FROM employee e
INNER JOIN salary s ON e.id = s.id
GROUP BY name, s.salary
ORDER BY name;

create temporary table sum
select r.id, sum(count) as sum
from rates r;

select * from rates
LEFT OUTER JOIN sum s ON r.id = s.id;

我尝试过自我加入，但这并不奏效。

提前致谢！

Answer 1

您需要在薪水和员工表之间执行内部联接

您还希望包含嵌套的SELECT语句。

SELECT e.id, e.name, s.salary, 
(SELECT COUNT(*) FROM salary s
       WHERE employee_id = id) as COUNT
FROM employees e
INNER JOIN salary s ON employees.id = salary.id

这是一个小提琴

http://sqlfiddle.com/#!9/b94ec/9/0

Answer 2

这是SQL Server代码，可以为您提供所需的结果。

    select 
        s.empid, e.name, s.salary,
        cnt.SalaryCount
    from 
        salary s
        inner join emp e on s.empid = e.id
        outer apply
        (select count(*) as SalaryCount from salary where empid = e.id) cnt

如何计算行并仍然显示所有行？ MySQL的

2 个答案: