Question

我是cakephp的新手，我有这样的困难：

从这个SQL查询开始：

         select service_group.name as service_group_name, service_group.id as service_group_id, campaign.name as campaign_name, campaign.id as campaign_id
      from group_service
      join group_service_campaign on group.service.id = group_service_campaign.group_service_id
      join campaign on group_service_campaign.campaign_id = campaign.id
      where campaign.active = 'Y'
      and campaign.id in ($in)
      and campaign.company_id = ${_SESSION['companyId']}
      order by group_service.name, campaign.name

我在控制器中将其转换为此内容：

$var_campaign = $this->loadModel('Service_Group');
$var_campaign = $this->Group_Service->find('list', ['keyfield' => 'campaign_id', 'valueField' => 'campaign_name', 'groupField' => 'service_group_name'])
            ->join(['table' => 'service_group_campaign',
                'type' => 'inner',
                'conditions' => 'Service_Group.id = service_group_campaign.service_group_id'
            ])
            ->join(['table' => 'campaign',
        'type' => 'inner',
        'conditions' => 'service_group_campaign.campaign_id = campaign.id'
    ]);
    $var_campaign->where(['campaign.active' => 'Y']);
    $var_campaign->order(['grou_service.name,campaign.name']);

我很难用这个来创建一个带有optgroup的select表单元素。我搜索的示例和问题类似，但我尝试过的都没有工作。

我的观点：

echo $this->Form->create();
echo $this->Form->input('id', array('label' => 'Services :', 'type' => 'select', 'empty'=> '-- Select --', 'options' => $var_campaign));
echo $this->Form->select("field", $var_campanha);

echo $this->Form->end();

当我在查询语句中使用find（＆＃39; list＆＃39; ...）时，我得到一个空白的回复，如果我使用find（＆＃39; all＆＃39; ...）我得到一个没有完整的回复，因为所有的广告系列名称都没有回复，只有服务组名称带有他们的ID。

我的optgroup显示如下纯文本：

{＆＃34; id＆＃34;：-1，＆＃34; name＆＃34;：＆＃34; Active Proposals＆＃34;，＆＃34; mod＆＃34;：＆＃34; W＆＃ 34;，＆＃34; company_id＆＃34;：10}

等等。

我哪里出错？

提前感谢。

使用cakephp创建一个optgroup

0 个答案: