Question

你能告诉我这里我做错了什么吗？我真的很难为Hazelcast实现更高效的串行器。我有以下Java类：

public class Tuple<X, Y> implements DataSerializable
{ 
    public X x;
    public Y y;

    private Tuple()
    {
    }

    public Tuple(X x, Y y)
    { 
        this.x = x; 
        this.y = y; 
    }

    @Override
    public void readData(ObjectDataInput in)
            throws IOException {
        Instance.log("read data");
        this.x = (X)in.readObject();
        this.y = (Y)in.readObject();
    }

    @Override
    public void writeData(ObjectDataOutput out)
            throws IOException {
        Instance.log("write data");
        out.writeObject(this.x);
        out.writeObject(this.y);
    }

}

我正在使用它：

HazelcastInstance hazelcast = Hazelcast.newHazelcastInstance();
IMap<String, Set<Tuple<Integer, Double>>> myMap = Hazelcast.getMap("myMap");

然而，每当我试图使用这个地图时（除了实现Serializable，那个场景工作正常）我就会回到这个例外：

com.hazelcast.nio.serialization.HazelcastSerializationException: java.io.NotSerializableException: Tuple

我在这里做错了什么？感谢任何想法，万分感谢！

更新

尝试过这个建议（感谢noctarius）我现在有了这个：

public class TupleSetStreamSerializer
        implements StreamSerializer<Set<Tuple>> {

    @Override
    public int getTypeId () {
        return SerializationIdentifiers.TupleSerializationFactoryId;
    }

    @Override
    public void write(ObjectDataOutput out, final Set<Tuple> set )
            throws IOException {
        int size = set == null ? 0 : set.size();
        Instance.log("Serialize set");
        out.writeInt(size);
        if (size>0) {
            Iterator iterator = set.iterator();
            while (iterator.hasNext()) {
                out.writeObject(iterator.next());
            }
        }
    }

    @Override
    public Set<Tuple> read( ObjectDataInput in )
            throws IOException {

        Instance.log("Deserialize set");
        int size = in.readInt();
        Set result = null;
        if (size > 0) {
            result = new HashSet<Tuple>();
            for (int i = 0; i < size; i++) {
                result.add(in.readObject());
            }
        }
        return result;
    }

    @Override
    public void destroy () {
    }
}

这也是

public class TupleStreamSerializer
        implements StreamSerializer<Tuple> {

    @Override
    public int getTypeId () {
        return SerializationIdentifiers.TupleSerializationFactoryId;
    }

    @Override
    public void write(ObjectDataOutput out, Tuple tup )
            throws IOException {
        out.writeObject(tup.x);
        out.writeObject(tup.y);
    }

    @Override
    public Tuple read( ObjectDataInput in )
        throws IOException {
        Object x = in.readObject();
        Object y = in.readObject();
        return new Tuple(x,y);
    }

    @Override
    public void destroy () {
    }
}

使用这样的配置（尝试评论各种变体和所有）

<hazelcast>
    <serialization>
        <serializers>
            <serializer type-class="Tuple">TupleStreamSerializer</serializer>
            <serializer type-class="Set<Tuple>">TupleSetStreamSerializer</serializer>
        </serializers>
    </serialization>
</hazelcast>

我似乎仍然缺少某些东西？非常感谢！

Answer 1

您必须为Set接口编写特殊的StreamSerializer。每当Hazelcast开始序列化Serializable标记类时，它就会失去序列化控制。有一些解决方法，但所有这些都不是很好。最好的方法是使用Serializable拦截Set的序列化并提供自定义序列化器：http://docs.hazelcast.org/docs/3.5/manual/html-single/index.html#streamserializer

您将在Hazelcast核心代码中找到LinkedList类型的示例：https://github.com/hazelcast/hazelcast/blob/master/hazelcast/src/main/java/com/hazelcast/internal/serialization/impl/LinkedListStreamSerializer.java

当包含泛型类型时，如何通过Hazelcast DataSerializable序列化Java类？

1 个答案: