Question

我想要的是

if((TRAVIS_BRANCH != "master") || (TRAVIS_BRANCH == "master" && TRAVIS_PULL_REQUEST == true)

我如何在bash中执行此操作？我认为这是最接近的，但它仍然不起作用

if [ "$TRAVIS_BRANCH" != "master" ] || ["$TRAVIS_BRANCH" == "master" &&  "$TRAVIS_PULL_REQUEST" == "true"]

Answer 1

在命令名称周围添加空格（[是命令名称），不要在单个&&命令中尝试使用||或[。

if [ "$TRAVIS_BRANCH" != "master" ] || { [ "$TRAVIS_BRANCH" = "master" ] && [ "$TRAVIS_PULL_REQUEST" = "true"]; }

但是，您可以在&&内使用||或[[ ]]，并且也不需要在那里引用：

if [[ $TRAVIS_BRANCH != master ]] || [[ $TRAVIS_BRANCH = master && $TRAVIS_PULL_REQUEST = true ]]

Answer 2

确保[和]字符被空格包围
Double equals在Bash中有效，但与POSIX不兼容
您必须在-a

&&

[

由于shell代码中的difficulty in working out the precedence rules，建议每行代码不要使用多个布尔运算符
建议在Bash中使用[[而不是[

结果：

is_master_pull_request() {
    [[ "$TRAVIS_BRANCH" = "master" ]] && [[ "$TRAVIS_PULL_REQUEST" = "true" ]]
}
if [[ "$TRAVIS_BRANCH" != "master" ]] || is_master_pull_request

Answer 3

尝试：

if [ "$TRAVIS_BRANCH" != "master" ] || [[ "$TRAVIS_BRANCH" == "master" && "$TRAVIS_PULL_REQUEST" == "true" ]]; then

如果bash中有多个组的声明？

3 个答案: