我的查询大部分都正常运行，但根据屏幕截图here和下面的示例，我遇到了以下问题：
1）Expr1列返回我通过查询请求的正确总数，但正如您所见，通过COMPANY重复。使用DISTINCT没有帮助，我的子查询是我如何检索由COMPANY描绘的总数，但它仍然显示重复的值。
2）关于如何在每个公司获得一行Expr1的总量的建议是我正在拍摄的。谢谢。
这是我的代码：
SELECT Activity.ACTIVITY_TYPE,
Activity.TRANSACTION_DATE,
Activity.PRODUCT_CODE,
Activity.DESCRIPTION,
Name.ID,
Name.MEMBER_TYPE,
Name.STATUS,
Name.COMPANY,
Demo_Chapter.CH_COL_REGION,
Demo_Ch_Membership.CM_CURRENT_INIT,
Demo_Chapter.CH_CHAP_NUMBER,
(SELECT DISTINCT COUNT(a2.PRODUCT_CODE) AS Expr1
FROM Activity AS a2 INNER JOIN
Name AS n2 ON a2.ID = n2.ID
WHERE (n2.COMPANY = Name.COMPANY)
AND (a2.PRODUCT_CODE = 'aaol')
AND (a2.TRANSACTION_DATE BETWEEN CONVERT(DATETIME, '2015-08-01 00:00:00', 102)
AND CONVERT(DATETIME, '2016-07-31 00:00:00', 102))
GROUP BY n2.COMPANY) AS Expr1
FROM Name INNER JOIN
Demo_Individual ON Name.ID = Demo_Individual.ID
INNER JOIN
Activity ON Name.ID = Activity.ID
INNER JOIN
Demo_Chapter ON Name.CO_ID = Demo_Chapter.ID
INNER JOIN
Demo_Ch_Membership ON Name.CO_ID = Demo_Ch_Membership.ID
WHERE (Name.MEMBER_TYPE = 'COL')
AND (Name.STATUS IN ('A', 'ABR'))
AND (Activity.ACTIVITY_TYPE IN ('FIDELITY', 'FIDELITYOL'))
AND (Activity.TRANSACTION_DATE BETWEEN CONVERT(DATETIME, '2015-08-01 00:00:00', 102) AND CONVERT(DATETIME, '2016-07-31 00:00:00', 102))
AND (Activity.PRODUCT_CODE = 'aaol')
以下是输出样本（注意重复信息）：
CH_CHAP_NUMBER COMPANY CH_Col_REGION CM_CURRENT_INIT Expr1
--------------------------------------------------------------------------
024 Omega Chapter REG_5 160 121
024 Omega Chapter REG_5 160 121
161 Zeta Rho Chapter REG_3 282 162
161 Zeta Rho Chapter REG_3 282 162
161 Zeta Rho Chapter REG_3 282 162
etc
所需的输出如下：
CH_CHAP_NUMBER COMPANY CH_Col_REGION CM_CURRENT_INIT Expr1
--------------------------------------------------------------------------
024 Omega Chapter REG_5 160 121
161 Zeta Rho Chapter REG_3 282 162
etc
更广泛的完成输出：
ACTIVITY_TYPE TRANSACTION_DATE PRODUCT_CODE MEMBER_TYPE STATUS COMPANY CH_COL_REGION CM_CURRENT_INIT CH_CHAP_NUMBER Expr1
------------- ----------------------- ------------------------------- ----------- ------ -------------------------------------------------------------------------------- ------------------------------ --------------- -------------- -----------
FIDELITYOL 2015-09-01 13:18:00.000 AAOL COL A Omega Chapter REG_5 160 024 121
FIDELITYOL 2015-09-01 11:47:00.000 AAOL COL A Omega Chapter REG_5 160 024 121
FIDELITYOL 2015-09-01 21:24:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-09-07 15:39:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-08-31 12:23:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-12-07 00:00:00.000 AAOL COL A Gamma Psi Chapter REG_5 84 095 56
FIDELITYOL 2015-09-07 16:01:00.000 AAOL COL A Beta Sigma Chapter REG_8 172 066 6
FIDELITYOL 2015-09-08 09:14:00.000 AAOL COL A Beta Eta Chapter REG_5 127 055 85
FIDELITYOL 2015-09-07 22:44:00.000 AAOL COL A Epsilon Nu Chapter REG_7 189 133 129
FIDELITYOL 2015-08-31 20:50:00.000 AAOL COL A Epsilon Pi Chapter REG_2 149 136 68
FIDELITYOL 2015-09-01 08:03:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-08-31 22:19:00.000 AAOL COL A Epsilon Pi Chapter REG_2 149 136 68
FIDELITYOL 2015-09-05 16:29:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-09-07 22:25:00.000 AAOL COL A Beta Sigma Chapter REG_8 172 066 6
FIDELITYOL 2015-09-01 20:58:00.000 AAOL COL A Beta Sigma Chapter REG_8 172 066 6
FIDELITYOL 2015-09-07 13:25:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-09-07 16:14:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-09-04 23:34:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
FIDELITYOL 2015-09-07 14:27:00.000 AAOL COL A Zeta Rho Chapter REG_3 282 161 162
答案 0 :(得分：0)
你能看出这是否有效，在不知道你的数据是什么的情况下很难说清楚：
DECLARE @transDateStart DATETIME='20150801';
DECLARE @transDateEnd DATETIME='20160731';
DECLARE @productCode VARCHAR(10) = 'aaol';
WITH CompanyActivityCount
AS
(SELECT DISTINCT COUNT(a2.PRODUCT_CODE) AS Expr1,
n2.COMPANY
FROM Activity AS a2
INNER JOIN
Name AS n2
ON a2.ID = n2.ID
WHERE a2.PRODUCT_CODE = @productCode
AND a2.TRANSACTION_DATE BETWEEN @transDateStart AND @transDateEnd
GROUP BY n2.COMPANY
)
SELECT DISTINCT Activity.ACTIVITY_TYPE,
Activity.TRANSACTION_DATE,
Activity.PRODUCT_CODE,
Activity.DESCRIPTION,
Name.ID,
Name.MEMBER_TYPE,
Name.STATUS,
Name.COMPANY,
Demo_Chapter.CH_COL_REGION,
Demo_Ch_Membership.CM_CURRENT_INIT,
Demo_Chapter.CH_CHAP_NUMBER,
CompanyActivityCount.Expr1
FROM Name
INNER JOIN
Demo_Individual
ON Name.ID = Demo_Individual.ID
INNER JOIN
Activity
ON Name.ID = Activity.ID
INNER JOIN
Demo_Chapter
ON Name.CO_ID = Demo_Chapter.ID
INNER JOIN
Demo_Ch_Membership
ON Name.CO_ID = Demo_Ch_Membership.ID
LEFT OUTER JOIN
CompanyActivityCount
ON CompanyActivityCount.COMPANY = Name.COMPANY
WHERE Name.MEMBER_TYPE = 'COL'
AND Name.STATUS IN ('A', 'ABR')
AND Activity.ACTIVITY_TYPE IN ('FIDELITY', 'FIDELITYOL')
AND Activity.TRANSACTION_DATE BETWEEN @transDateStart AND @transDateEnd
AND Activity.PRODUCT_CODE = @productCode;
由于没有嵌套的子查询，它应该会更好一些。
答案 1 :(得分：-2)
只需在选择
中使用DISTINCT即可