Question

我有一个表格可以改变名为＆＃34;发票＆＃34;的sql表。我想弹出一个bootstrap模式，它将改变一个名为＆＃34; customers＆＃34;的sql表。现在，唯一能够妥善保存的是客户名称...我错过了什么吗？这是我到目前为止的代码......

主页：

 type mismatch; found : List[String] required: org.json4s.JValue (which expands to) org.json4s.JsonAST.JValue

表单保存代码：

<!-- Modal Add Customer -->
     <div class="modal fade" id="addNewCustomer" tabindex="-1" role="dialog" aria-labelledby="addNewCustomerLabel">
      <div class="modal-dialog" role="document">
        <div class="modal-content">
          <div class="modal-header">
            <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
            <h4 class="modal-title" id="myModalLabel">Add New Customer</h4>
          </div>
           <div class="modal-body">
            <form action="<?php echo $_SERVER['PHP_SELF']; ?>" id="add_customer_form" method="post" class="form-horizontal myaccount" role="form">
            <div class="form-group col-lg-7">
                    <label for="customer_Name_modal">Customer Name (Last Name, First Name)</label>
                    <input type="text" class="form-control" id="customer_Name_modal" name="customer_Name_modal" placeholder="Last Name, First Name">
                    <span class="help-block"></span>
                </div>
            <div class="form-group col-lg-7">
                    <label for="customer_Phone_modal">Phone Number (555-555-5555)</label>
                    <input type="text" class="form-control" id="customer_Phone_modal" name="customer_Phone_modal" placeholder="555-555-5555">
                    <span class="help-block"></span>
                </div>
            <div class="form-group col-lg-7">
                    <label for="customer_Email_modal">Email (johndoe@gmail.com)</label>
                    <input type="text" class="form-control" id="customer_Email_modal" name="customer_Email_modal" placeholder="john@doe.com">
                    <span class="help-block"></span>
                </div>
            <div class="form-group col-lg-7">
                    <label for="customer_Address1_modal">Address Line 1 </label>
                    <input type="text" class="form-control" id="customer_Address1_modal" name="customer_Address1_modal" placeholder="">
                    <span class="help-block"></span>
                </div>
            <div class="form-group col-lg-7">
                    <label for="customer_Address2_modal">Address Line 2 </label>
                    <input type="text" class="form-control" id="customer_Address2_modal" name="customer_Address2_modal" placeholder="">
                    <span class="help-block"></span>
                </div>
            <input type="hidden" id="current_element_id">
        </form>
        </div>
        <div class="modal-footer">
            <button type="button" id="add_new_customer_btn" class="btn btn-primary" data-loading-text="Saving Customer...">Save changes</button>
            <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
          </div>
            </div>
            </div>
            </div>

Sql代码：

var save_new_customer = function(){

    $('#add_new_customer_btn').button('loading');

    data = {
            customerName : $('#customer_Name_modal').val(),
            customerPhone : $('#customer_Phone_modal').val(),
            customerEmail : $('#customer_Email_modal').val(),
            customerAddress1 : $('#customer_Address1_modal').val(),
            customerAddress2 : $('#customer_Address2_modal').val(),
    }


    $.ajax({
         url: "ajax.php",
         dataType: "json",
         method: 'post',
         data: {
            data : data,
            type: 'saveNewCustomer'
         },
         success: function(result){
            if( (typeof result.success !== "undefined") && result.success ){

                $("html, body").animate({ scrollTop: 0 }, "slow");
                $('#add_new_customer_btn').button('reset');

                $('#addNewCustomer').modal('show');
                element_id = $('#current_element_id').val();
                $('#customerName_'+element_id).val($('#customer_Name_modal').val());
                $('#phone_'+element_id).val( $('#customer_Email_modal').val() );
                $('#email_'+element_id).val($('#customer_Phone_modal').val());
                $('#addressLine1_'+element_id).val($('#customer_Address1_modal').val());
                $('#addressLine2_'+element_id).val($('#customer_Address2_modal').val());

                $('#add_customer_form')[0].reset();
                $('#add_customer_form').find("div.form-group").removeClass('has-success');
                $('#message_h1').show();
                message('success', CUSTOMER_ADD_SUCCESS);
            }else{
                message('fail', CUSTOMER_ADD_FAIL);
            }
        }
     });


}

Answer 1

您在PHP中使用了错误的密钥

您正在拨打这些密钥：

$customerName = mysqli_real_escape_string( $db->con, trim( $data['customerName'] ) );
$customerPhone = mysqli_real_escape_string( $db->con, trim( $data['phone'] ) );
$customerEmail = mysqli_real_escape_string( $db->con, trim( $data['email'] ) );
$customerAddress1 = mysqli_real_escape_string( $db->con, trim( $data['addressLine1'] ) );
$customerAddress2 = mysqli_real_escape_string( $db->con, trim( $data['addressLine2'] ) );

但你应该打电话：

$customerName = mysqli_real_escape_string( $db->con, trim( $data['customerName'] ) );
$customerPhone = mysqli_real_escape_string( $db->con, trim( $data['customerPhone'] ) );
$customerEmail = mysqli_real_escape_string( $db->con, trim( $data['customerEmail'] ) );
$customerAddress1 = mysqli_real_escape_string( $db->con, trim( $data['customerAddress1'] ) );
$customerAddress2 = mysqli_real_escape_string( $db->con, trim( $data['customerAddress2'] ) );

要解决此问题，只需在SQL代码中复制并粘贴（替换）变量赋值。

使bootstrap模式使用单独的表单/ sql表

1 个答案: