我正在使用谷歌地图api并使用网格聚类作为标记。我想知道是否有办法从群集中排除单个标记。我想要一个始终可见的“你在这里”标记。我尝试使用不同的数组仅用于该标记,并且不包括它的集群功能,但这不起作用。
有人有解决方案吗?
以下是我如何进行聚类
$(document).on('click', '#mapbut', function() {
var items, distances, you_are_here = [], markers_data = [], markers_data2 = [], fred, clust1, markss;
you_are_here.push({
lat : Geo.lat,
lng : Geo .lng,
animation: google.maps.Animation.DROP,
title : 'Your are here',
icon: {
path: google.maps.SymbolPath.CIRCLE,
scale: 10
},
infoWindow: {
content: '<p>You are Here</p>'
}
});
function loadResults (data) {
if (data.map.length > 0) {
items = data.map;
for (var i = 0; i < items.length; i++)
{
var item = items[i];
var distances = [];
var dist2;
if (item.Lat != undefined && item.Lng != undefined)
{
markers_data.push({
lat : item.Lat,
lng : item.Lng,
title : item.Site,
infoWindow: {
content: '<p>' + item.Site + '</p><p>' + Math.round(item.distance) + ' miles away</p>'
}
});
}
}
}
map.addMarkers(markers_data);
map = new GMaps({
el: '#map',
lat: Geo.lat,
lng: Geo.lng,
zoom: 10,
mapTypeControl: false,
zoomControl: true,
zoomControlOptions: {
position: google.maps.ControlPosition.LEFT_CENTER
},
markerClusterer: function(map) {
options = {
gridSize: 50
}
clust1 = new MarkerClusterer(map,[], options);
return clust1;
},
scaleControl: true,
streetViewControl: false
});
map.addMarkers(you_are_here);
答案 0 :(得分:3)
GMaps
使用addMarker
方法对您添加到其中的所有标记进行聚类(如果您提供MarkerClusterer)。
一个选项:添加您的&#34;特殊&#34;标记(您不希望群集的标记)手动添加到地图中,因此不会将其添加到MarkerClusterer
:
GMaps.map
属性是对Google Maps Javascript API v3地图对象的引用。因此,这将为地图添加标记,而不让GMaps
库知道它:
you_are_here = new google.maps.Marker({
position: {lat: Geo.lat,lng: Geo.lng},
animation: google.maps.Animation.DROP,
title: 'Your are here',
icon: {
path: google.maps.SymbolPath.CIRCLE,
scale: 10
},
map: map.map
});
代码段
var Geo = {
lat: 40.7281575,
lng: -74.07764
};
$(document).on('click', '#mapbut', function() {
var items, distances, you_are_here = [],
markers_data = [],
markers_data2 = [],
fred, clust1, markss;
function loadResults(data) {
if (data.map.length > 0) {
items = data.map;
for (var i = 0; i < items.length; i++) {
var item = items[i];
var distances = [];
var dist2;
if (item.Lat != undefined && item.Lng != undefined) {
markers_data.push({
lat: item.Lat,
lng: item.Lng,
title: item.Site,
infoWindow: {
content: '<p>' + item.Site + '</p><p>' + Math.round(item.distance) + ' miles away</p>'
}
});
}
}
}
map = new GMaps({
el: '#map',
lat: Geo.lat,
lng: Geo.lng,
zoom: 8,
mapTypeControl: false,
zoomControl: true,
zoomControlOptions: {
position: google.maps.ControlPosition.LEFT_CENTER
},
markerClusterer: function(map) {
options = {
gridSize: 50,
imagePath: "https://cdn.rawgit.com/googlemaps/v3-utility-library/master/markerclustererplus/images/m"
}
clust1 = new MarkerClusterer(map, [], options);
return clust1;
},
scaleControl: true,
streetViewControl: false
});
map.addMarkers(markers_data);
you_are_here = new google.maps.Marker({
position: {
lat: Geo.lat,
lng: Geo.lng
},
animation: google.maps.Animation.DROP,
title: 'Your are here',
icon: {
path: google.maps.SymbolPath.CIRCLE,
scale: 10
},
infoWindow: {
content: '<p>You are Here</p>'
},
map: map.map
});
// map.addMarkers(you_are_here);
}
loadResults(data);
});
var data = {
map: [{
Lat: 40.7127837,
Lng: -74.005941,
Site: "New York, NY",
distance: 1
}, {
Site: "Newark, NJ",
Lat: 40.735657,
Lng: -74.1723667,
distance: 2
}]
};
&#13;
html,
body,
#map {
height: 100%;
width: 100%;
margin: 0px;
padding: 0px
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maps.googleapis.com/maps/api/js"></script>
<script src="https://rawgit.com/HPNeo/gmaps/master/gmaps.js"></script>
<script src="https://cdn.rawgit.com/googlemaps/v3-utility-library/master/markerclustererplus/src/markerclusterer.js"></script>
<input id="mapbut" type="button" value="map" />
<div id="map"></div>
&#13;
答案 1 :(得分:0)
为了解决这个问题相对简单,就在我将markers数组发送到MarkerClusterer后,我就添加了我的位置。
// Setup cluster markers
var markerCluster = new MarkerClusterer( gmap.map, options )
// add my location
gmap.addMarker({
lat: data.latitude,
lng: data.longitude
...
})
由于