Question

我在启用Spring-Boot JPA的项目（All Groovy Code）中有以下相关的JPA注释类：

@Entity
abstract class Character {
    @Id
    String id;

    String name;

    @ElementCollection(targetClass = Episode)
    @Enumerated(EnumType.ORDINAL)
    Collection<Episode> appearsIn;
}

@Entity(name = "Human")
public class Human extends Character {
    String homePlanet;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "favorite_droid_id")
    Droid favoriteDroid;
}

public enum Episode {
    PHANTOM_MENACE,
    ATTACK_OF_THE_CLONES,
    REVENGE_OF_THE_SITH,
    A_NEW_HOPE,
    EMPIRE_STRIKES_BACK,
    RETURN_OF_THE_JEDI,
    THE_FORCE_AWAKENS
}

当我尝试执行以下JPA查询时：

def query = em.createQuery("from Human h where h.appearsIn in (:episodes)");
query.setParameter("episodes", EnumSet.of(Episode.THE_FORCE_AWAKENS));
def result = query.getResultList();

生成的SQL语句似乎没有Character表的别名或者出现的列名：

select human0_.id as id2_0_, human0_.name as name3_0_, human0_.favorite_droid_id as favorite6_0_, human0_.home_planet as home_pla5_0_ 
from character human0_ 
cross join character_appears_in appearsin1_ 
where human0_.dtype='Human' and human0_.id=appearsin1_.character_id and (. in (?))

我也尝试过使用equals而不是in，具有相同的行为：

from Human h where h.appearsIn = :episode

生成以下SQL：

select human0_.id as id2_0_, human0_.name as name3_0_, human0_.favorite_droid_id as favorite6_0_, human0_.home_planet as home_pla5_0_ 
from character human0_ 
cross join character_appears_in appearsin1_ 
where human0_.dtype='Human' and human0_.id=appearsin1_.character_id and .=?

非常感谢任何帮助。

Answer 1

您的查询无效 - 正如@Neil Stockton指出的那样，通过编写h.appearsIn in (:episodes)，您正在说＆＃34;集合中的集合＆＃34;没有意义。

你应该声明一个＆＃34;集合成员变量＆＃34;像这样：

select distinct h
from Human h 
join h.appearsIn ai
where ai in (:episodes)

ai表示appearsIn的单个元素（就像迭代器一样）。

JPA Query缺少别名和列（Hibernate）

1 个答案: