在我的项目中,我使用HSQLDB作为数据库。构建了DB并添加了两个条目。现在我试图用JPA获取这些条目。不幸的是,得到以下异常
错误:用户缺少未找到的权限或对象:BOOK javax.persistence.PersistenceException:org.hibernate.exception.SQLGrammarException:无法准备语句 在org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1692) 在org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1602) 在org.hibernate.jpa.internal.QueryImpl.getResultList(QueryImpl.java:492) 在com.top.shelf.lib.entityManagers.BookManager.main(BookManager.java:48) 引起:org.hibernate.exception.SQLGrammarException:无法准备语句 在org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:63) 在org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:42) 在org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:109) at org.hibernate.engine.jdbc.internal.StatementPreparerImpl $ StatementPreparationTemplate.prepareStatement(StatementPreparerImpl.java:182) 在org.hibernate.engine.jdbc.internal.StatementPreparerImpl.prepareQueryStatement(StatementPreparerImpl.java:148) 在org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1928) 在org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1897) 在org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1875)
这是我的persistance.xml
文件。
<class>com.top.shelf.lib.entityManager.Book</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:hsqldb:MyDB" />
<property name="javax.persistence.jdbc.user" value="sa" />
<property name="javax.persistence.jdbc.password" value="" />
<property name="javax.persistence.jdbc.driver" value="org.hsqldb.jdbcDriver" />
<property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect" />
</properties>
</persistence-unit>
我的实体班:
@Entity
@Table(name = "BOOK")
public class Book {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
private int id;
@Column(name = "TITLE")
private String title;
@Column(name = "AUTHOR")
private String author;
@Column(name = "BRIEF_DESCRIPTION")
private String description;
@Column(name = "ISBN")
private String isbn;
@Column(name = "LOCATION")
private String location;
@Column(name = "USER_ID")
private String user_id;
public Book(String title, String author, String description, String isbn,
String location) {
this.title = title;
this.author = author;
this.description = description;
this.isbn = isbn;
this.location = location;
}
public int getId() {
return id;
}
public String getTitle() {
return title;
}
public String getAuthor() {
return author;
}
public String getDescription() {
return description;
}
public String getIsbn() {
return isbn;
}
public String getLocation() {
return location;
}
public String getUser_id() {
return user_id;
}
}
答案 0 :(得分:2)
尝试:
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0">
<persistence-unit name="manager" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.top.shelf.lib.entityManager.Book</class>
<properties>
<property name="javax.persistence.jdbc.driver" value="org.hsqldb.jdbcDriver"/>
<property name="javax.persistence.jdbc.url" value="jdbc:hsqldb:MyDB"/>
<property name="javax.persistence.jdbc.user" value="sa"/>
<property name="javax.persistence.jdbc.password" value=""/>
<property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
</properties>
</persistence-unit>
</persistence>