Question

我正在尝试制作一个程序，以找出两个小时之间的差异。程序在所有小时内搜索到mongoDB的数据库，每次都必须找到它们之间的差异。但是我不知道如何在循环中每次都给出第二个值。

到现在为止，我找到一次并从一个标准中减去。

我每次都可以在循环中搜索前两个时间值。

非常感谢你的帮助!!!

    int count = 1;
    int start = 1;

    while (cursorEvents.hasNext()) {

        DBObject documentInEventCollection = cursorEvents.next();


        if("pageLoad".equals(documentInEventCollection.get("type"))){ 

            System.out.println("URL(" + count + "): " + documentInEventCollection.get("url").toString());
            System.out.println("time-start(" + start + "): " + documentInEventCollection.get("timeStamp").toString());
            count++;
            start++;

    try {
    String timeStart = (documentInEventCollection.get("timeStamp").toString());

    String timeStop = ("2015-07-24;12:26:54");

    SimpleDateFormat format = new SimpleDateFormat("yyyy-dd-MM;HH:mm:ss");

    Date d1 = null;
    Date d2 = null;


        d1 = format.parse(timeStart);
        d2 = format.parse(timeStop);

        //in milliseconds
        long diff = d2.getTime() - d1.getTime();

        long diffSeconds = diff / 1000 % 60;
        long diffMinutes = diff / (60 * 1000) % 60;
        long diffHours = diff / (60 * 60 * 1000) % 24;
        long diffDays = diff / (24 * 60 * 60 * 1000);

        System.out.print(diffDays + " days, ");
        System.out.print(diffHours + " hours, ");
        System.out.print(diffMinutes + " minutes, ");
        System.out.print(diffSeconds + " seconds.");

    } catch (Exception e) {
        e.printStackTrace();
    }
   }            
   }

Answer 1

我使用以下解决方案来计算不同的时间：

//Compute the time diff
Map<TimeUnit, Long> deltaTime = computeDiff(now.getTime(), target.getTime());

//Get the specific values            
long d = deltaTime.get(TimeUnit.DAYS);
long m = deltaTime.get(TimeUnit.MINUTES); 
long s = deltaTime.get(TimeUnit.SECONDS);

Methode代码：

 private static Map<TimeUnit, Long> computeDiff(Date start, Date end) {
            long diffMilTime = end.getTime() - start.getTime();
            List<TimeUnit> units = new ArrayList<>(EnumSet.allOf(TimeUnit.class));
            Collections.reverse(units);

            Map<TimeUnit, Long> result = new LinkedHashMap<>();
            long restMilTime = diffMilTime;
            for (TimeUnit unit : units) {
                long diff = unit.convert(restMilTime, TimeUnit.MILLISECONDS);
                long diffInMilliesForUnit = unit.toMillis(diff);
                restMilTime = restMilTime - diffInMilliesForUnit;
                result.put(unit, diff);
            }
            return result;
        }

如何找到时间之间的差异

1 个答案: