我正在尝试查询一个单词,因为我正在使用db.query方法。但我想使用 WHERE 子句。我在我的代码上做了这样的事情,但我想我的 WHERE 子句有问题。
public String select(String wrd) {
String list = new String();
Cursor cursor = this.db.query(TABLE_NAME, new String[] {"word"},
"word like " + wrd + "", null, null, null, "id desc");
if (cursor.moveToNext()) {
do {
list = cursor.getString(0);
} while (cursor.moveToNext());
}
if (cursor != null && !cursor.isClosed()) {
cursor.close();
}
return list;
}
我在其他类中调用此方法,解析String参数。
Cursor cursor = getContentResolver().query(CONTENT_URI, null, null, null, null);
String body;
if(cursor.moveToFirst()){
body = cursor.getString(cursor.getColumnIndexOrThrow("body")).toString();
if(body == ""){
Toast.makeText(getBaseContext(), "There is no words to save!", Toast.LENGTH_LONG).show();
}
else{
String words = this.dh.select("Testando");
StringTokenizer st = new StringTokenizer(body);
while(st.hasMoreTokens()){
if(words == st.nextToken())
Toast.makeText(getBaseContext(), "found! "+words+"", Toast.LENGTH_LONG).show();
this.dh.insert(st.nextToken());
Toast.makeText(getBaseContext(), "The set of words has been updated!", Toast.LENGTH_LONG).show();
}
StringBuilder sb = new StringBuilder();
sb.append("Set of words:\n\n");
sb.append(words + " ");
txtView.setText(sb.toString());
}
}
答案 0 :(得分:2)
我认为问题与下面代码中的双引号有关:
Cursor cursor = this.db.query(TABLE_NAME, new String[] {"word"},
"word like " + wrd + "", null, null, null, "id desc");
试试这个
Cursor cursor = this.db.query(TABLE_NAME, new String[] {"word"},
"word like \"" + wrd + "\"", null, null, null, "id desc");
甚至更好
Cursor cursor = this.db.query(TABLE_NAME, new String[] {"word"},
"word like ?",new String[] {wrd} , null, null, "id desc");
修改强>
在WHERE子句中使用单引号而不是双引号。见here
Cursor cursor = this.db.query(TABLE_NAME, new String[] {"word"},
"word like \'" + wrd + "\'", null, null, null, "id desc");