我想使用下表在sql中进行连接以获取课堂详细信息:
表1:Student
+----+------+---------------+
| ID | NAME | SUBJECT |
+----+------+---------------+
| 1 | ABC | Science,Maths |
| 2 | XYZ | Geo, |
| 3 | XCZ | Mar,Hin |
+----+------+---------------+
表2:ClassRoom
+----------+-----------+
| Subject | ClassRoom |
+----------+-----------+
| Science | 1 |
| Maths | 2 |
| Geo | 3 |
| Mar | 4 |
| Hin | 5 |
+----------+-----------+
我希望输出显示各个主题的所有教室,例如第一桌科学,数学应该采取不同的方式
select * from [Student]
left join [ClassRoom]
on [Student].SUBJECT= [ClassRoom].Subject
Expected Output:-
+----------+------+---------------+
| ClassRoom| NAME | SUBJECT |
+----------+------+---------------+
| 1 | ABC | Science |
| 2 | ABC | Maths |
| 3 | XYZ | Geo |
| 4 | XCZ | Mar |
| 5 | XCZ | Hin |
+----------+------+---------------+
答案 0 :(得分:1)
如果这两个表格字段都是LEFT JOIN
,则可以LIKE
String
SELECT *
FROM [Student]
LEFT JOIN [ClassRoom] ON [Student].SUBJECT LIKE '%' + [ClassRoom].SUBJECT + '%'
。
scanf
答案 1 :(得分:1)
您可以使用LIKE
声明
SELECT
b.classroom, a.name, b.subject
FROM Student a
LEFT JOIN JOIN Classroom b
ON a.subject LIKE '%' + b.subject + '%'