Question

我按照https://developers.google.com/identity/sign-in/ios/sdk/上的说明将google登录整合到我的swift项目中。您可能知道登录成功时会调用以下函数。它被调用，但我无法弄清楚我如何只获得字段user.profile.name的名字和姓氏。我只获得全名，但出于我的目的，我需要将名称分开： - （

func signIn(signIn: GIDSignIn, didSignInForUser user: GIDGoogleUser, withError error: NSError) {
// Perform any operations on signed in user here.
var userId: String = user.userID
// For client-side use only!
var idToken: String = user.authentication.idToken
// Safe to send to the server
var name: String = user.profile.name
var email: String = user.profile.email
}

有人可以向我解释我是如何得到这些信息的吗？

菲尔

Answer 1

好的...所以经过几个小时的Google参考搜索后，我发现了一些有趣的Google API和OAuth https://developers.google.com/identity/protocols/OAuth2我们可以通过查询https://www.googleapis.com/oauth2/v3/userinfo?access_token=获取更多信息（感谢这个问题） What are the end points to get the emailId using oauth for the google, yahoo, twitter service providers?）我发现，如果用户已成功登录，我可以通过身份验证令牌获取大量信息...我不认为应该使用google +上面的解决方案，因为他们使用旧的SDK https://developers.google.com/+/mobile/ios/upgrading-sdk（您需要使用这些内容，例如GTLServicePlus）使用OAuth和最新的谷歌SDK解决方案更加安全（为了将来的目的） - ＆gt; https://developers.google.com/identity/sign-in/ios/start

但感谢您的回答： - ）

对于任何有相同问题的人，以下代码应该有效 - ＆gt;

欢呼声菲尔

编辑：谢谢jcaron！事实上那会更好的异步忘记这样做 - ＆gt;更新了解决方案

func signIn(signIn: GIDSignIn!, didSignInForUser user: GIDGoogleUser!, withError error: NSError!) {
    if (error == nil) {
        var firstName = ""
        var lastName = ""

        UIApplication.sharedApplication().networkActivityIndicatorVisible = true
        let url = NSURL(string:  "https://www.googleapis.com/oauth2/v3/userinfo?access_token=\(user.authentication.accessToken)")
        let session = NSURLSession.sharedSession()
        session.dataTaskWithURL(url!) {(data, response, error) -> Void in
            UIApplication.sharedApplication().networkActivityIndicatorVisible = false
            do {
                let userData = try NSJSONSerialization.JSONObjectWithData(data!, options:[]) as? [String:AnyObject]
                /*
                Get the account information you want here from the dictionary
                Possible values are
                "id": "...",
                "email": "...",
                "verified_email": ...,
                "name": "...",
                "given_name": "...",
                "family_name": "...",
                "link": "https://plus.google.com/...",
                "picture": "https://lh5.googleuserco...",
                "gender": "...",
                "locale": "..."

                so in my case:
                */
                firstName = userData!["given_name"] as! String
                lastName = userData!["family_name"] as! String
                print(firstName)
                print(lastName)
            } catch {
                NSLog("Account Information could not be loaded")
            }
        }.resume()
    }
    else {
        //Login Failed
    }
}

Answer 2

这与我们在制作中的内容类似：

private func finishAuthorizationForUser(signInUser: GIDGoogleUser) {

    let servicePlus = GTLServicePlus()
    servicePlus.authorizer = signInUser.authentication.fetcherAuthorizer()
    servicePlus.fetchObjectWithURL(NSURL(string: "https://www.googleapis.com/plus/v1/people/me")!, completionHandler: { (ticket, object, error) -> Void in

        guard error == nil else {
            self.showUnsuccessfulLoginAlertWithMessage(error.description)
            return
        }

        guard let user = object as? GTLObject else {
            self.showUnsuccessfulLoginAlertWithMessage("Bad user")
            return
        }

        let userJson = NSDictionary(dictionary: user.JSON) as! [String: AnyObject]

        if let names = userJson["name"] as? [String: String] {
            let lastName = names["familyName"]
            let firstName = names["givenName"]
            //...do something with these names
        }
    })

}

Answer 3

你知道最后一个字符串每次都是姓氏:)直到数组中的姓氏作为名字或名字。将最后一个字符串视为姓氏。最后你将得到一个包含两个字符串的数组。

Answer 4

您必须向Google+提出其他问题才能获取用户的详细信息。这需要将GooglePlus和GoogleOpenSource框架链接在其中。

这是Objective-C代码，对Swift的翻译留给了读者：

#import <Google/SignIn.h>
#import <GooglePlus/GooglePlus.h>
#import <GoogleOpenSource/GoogleOpenSource.h>

...

- (void)signIn:(GIDSignIn *)signIn
didSignInForUser:(GIDGoogleUser *)user
     withError:(NSError *)error
{
    if (error)
    {
        NSLog(@"Google sign-in error: %@", error);
        // do any cleanup like re-enabling buttons here
        return;
    }
    if (!user)
    {
        NSLog(@"Google sign-in returned nil user");
        // do any cleanup like re-enabling buttons here
        return;
    }

    NSLog(@"Google sign-in successfull: %@, userId: %@ token: %@ name: %@ email: %@",
          user,
          user.userID,
          user.authentication.idToken,
          user.profile.name,
          user.profile.email);

    NSString *userId = user.userID;               // For client-side use only!
    NSString *idToken = user.authentication.idToken; // Safe to send to the server
    NSString *name = user.profile.name;
    NSString *email = user.profile.email;
    __block NSString *firstName = @"";
    __block NSString *lastName = @"";
    __block NSString *title = @"";

    NSArray *nameComponents = [name componentsSeparatedByString:@" "];
    if (nameComponents.count == 2)
    {
        firstName = nameComponents[0];
        lastName = nameComponents[1];
    }

    GTMOAuth2Authentication *auth = [[GTMOAuth2Authentication alloc] init];
    [auth setClientID:signIn.clientID];
    [auth setUserEmail:user.profile.email];
    [auth setUserID:user.userID];
    [auth setAccessToken:user.authentication.accessToken];
    [auth setRefreshToken:user.authentication.refreshToken];
    [auth setExpirationDate: user.authentication.accessTokenExpirationDate];

    GTLServicePlus* plusService = [[GTLServicePlus alloc] init];
    plusService.retryEnabled = YES;
    plusService.authorizer = auth;
    GTLQueryPlus *query = [GTLQueryPlus queryForPeopleGetWithUserId:@"me"];

    [plusService executeQuery:query
            completionHandler:^(GTLServiceTicket *ticket,
                                GTLPlusPerson *person,
                                NSError *error)
     {
         if (error)
         {
             GTMLoggerError(@"Error: %@", error);
         }
         else
         {
             NSLog(@"me: %@, display name: %@, about me: %@, name: %@ / %@ gender: %@",
                   person, person.displayName, person.aboutMe, person.name.givenName, person.name.familyName, person.gender);
             firstName = person.name.givenName;
             lastName = person.name.familyName;
         }
         // do whatever you need with the data here
     }];
}

如何从Google登录获取名字和名字？

4 个答案: