Question

我想检查下面数组的2个值，并将数组B 上的值替换为0或1值（如果每个数组值与数组A 匹配或不匹配）。这是我的数组数据：

数组A ：

Array (
    [a1] => 2
    [a2] => 2
    [a3] => 3 )

数组B ：

Array (
[0] => Array
    (
        [a1] => 2
        [a2] => 1
        [a3] => 3
        [so] => 7
    )

[1] => Array
    (
        [a1] => 3
        [a2] => 2
        [a3] => 2
        [so] => 8
    )

[2] => Array
    (
        [a1] => 1
        [a2] => 3
        [a3] => 4
        [so] => 9
    ) )

这是我期望的输出：

知道如何在PHP中执行此操作吗？因为我仍然困惑如何将array_diff或array_intersect与foreach循环结合起来

Answer 1

也许不是最优雅的解决方案，但它确实有效：

$a = array
    (
        'a1' => 2,
        'a2' => 2,
        'a3' => 3
    );

$b = array ( 
    array
    (
        'a1' => 2,
        'a2' => 1,
        'a3' => 3,
        's0' => 7
    ),

    array
    (
        'a1' => 3,
        'a2' => 2,
        'a3' => 2,
        's0' => 8
    ),

    array
    (
        'a1' => 1,
        'a2' => 3,
        'a3' => 4,
        's0' => 9
    ) );


$c = array ();

$i=0;
foreach ($b as $b_row)
{
    $c[$i]['a1'] = ( $a['a1'] == $b_row['a1'] ) ? 1 : 0;
    $c[$i]['a2'] = ( $a['a2'] == $b_row['a2'] ) ? 1 : 0;
    $c[$i]['a3'] = ( $a['a3'] == $b_row['a3'] ) ? 1 : 0;
    $c[$i]['s0'] = $b_row['s0'];
    $i++;
}

或更紧凑：

$i=0;
foreach ($b as $b_row)
{
    foreach ($b_row as $b_cell => $value)
    {
        if (isset ($a[$b_cell])) 
        {
            $c[$i][$b_cell] = ( $a[$b_cell] == $value ) ? 1 : 0;
        }
        else 
        {
            $c[$i][$b_cell] = $value;
        }
    }
    $i++;
}

Answer 2

现在无法测试，但它可能是这样的

noexcept(std::is_nothrow_constructible<T>::value)

在PHP中检查两个数组的每个值

2 个答案: