我想抢先获取要加载到webView
的网页的HTML代码,使用正则表达式解析它,并只显示我想要的HTML代码,同时让网页仍然认为它装了一切。
有没有办法在WebViewClient.onLoadResource()
或类似的方法中做到这一点?
class MyJavaScriptInterface
{
@SuppressWarnings("unused")
public void showHTML(String html, Context context)
{
new AlertDialog.Builder(context)
.setTitle("HTML")
.setMessage(html)
.setPositiveButton(android.R.string.ok, null)
.setCancelable(false)
.create();
pageHTML = html;
}
}
@Override
public void customizeWebView(final ServiceCommunicableActivity activity, final WebView webview, final SearchResult mRom) {
mRom.setFileSize(getFileSize(mRom.getURLSuffix()));
webview.getSettings().setJavaScriptEnabled(true);
MyJavaScriptInterface interfaceA = new MyJavaScriptInterface();
webview.addJavascriptInterface(interfaceA, "HTMLOUT");
WebViewClient anchorWebViewClient = new WebViewClient()
{
@Override
public void onPageFinished(WebView view, String url)
{
/* This call inject JavaScript into the page which just finished loading. */
webview.loadUrl("javascript:window.HTMLOUT.showHTML('<head>'+document.getElementsByTagName('html')[0].innerHTML+'</head>');");
Pattern pattern = Pattern.compile("<h2>Winning Sc.+</h2></div>(.+)<br>", Pattern.DOTALL);
Matcher matcher = pattern.matcher(pageHTML);
matcher.find();
永远不会调用接口
答案 0 :(得分:10)
必须使用HttpClient。不需要cookie,只需解析html:
private String getDownloadButtonOnly(String url){
HttpGet pageGet = new HttpGet(url);
ResponseHandler<String> handler = new ResponseHandler<String>() {
public String handleResponse(HttpResponse response) throws ClientProtocolException, IOException {
HttpEntity entity = response.getEntity();
String html;
if (entity != null) {
html = EntityUtils.toString(entity);
return html;
} else {
return null;
}
}
};
pageHTML = null;
try {
while (pageHTML==null){
pageHTML = client.execute(pageGet, handler);
}
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Pattern pattern = Pattern.compile("<h2>Direct Down.+?</h2>(</div>)*(.+?)<.+?>", Pattern.DOTALL);
Matcher matcher = pattern.matcher(pageHTML);
String displayHTML = null;
while(matcher.find()){
displayHTML = matcher.group();
}
return displayHTML;
}
@Override
public void customizeWebView(final ServiceCommunicableActivity activity, final WebView webview, final SearchResult mRom) {
mRom.setFileSize(getFileSize(mRom.getURLSuffix()));
webview.getSettings().setJavaScriptEnabled(true);
WebViewClient anchorWebViewClient = new WebViewClient()
{
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
super.onPageStarted(view, url, favicon);
String downloadButtonHTML = getDownloadButtonOnly(url);
if(downloadButtonHTML!=null && !url.equals(lastLoadedURL)){
lastLoadedURL = url;
webview.loadDataWithBaseURL(url, downloadButtonHTML, null, "utf-8", url);
}
}
答案 1 :(得分:5)
以下是Extracting HTML from a WebView的教程,请不要忘记阅读本教程末尾的警告。
答案 2 :(得分:0)
尝试先添加@JavascriptInterface public void showHTML(String html,Context context)
答案 3 :(得分:0)
如果您有机会影响从中接收页面的服务器部分,您可以要求在出现错误时重定向到特定页面。在WebViewClient中,您可以检测到此重定向并使用错误信号。