SQL键值表 - 选择具有多个键的ID

Question

我需要在键值表中获取具有以下结构的记录：

CREATE TABLE `PROPERTY` (
  `id` int(11) NOT NULL,
  `key` varchar(64) NOT NULL,
  `value` text NOT NULL,
  PRIMARY KEY (`id`,`key`)
);

我需要获取具有MULTIPLE特定键值条目的所有ID。例如，所有具有键“foo”，“bar”和“foobar”的ID。

Answer 1

只需使用GROUP BY进行分组，然后检查组计数即可计算多个值：

Select 
    id
from 
    `PROPERTY`
group by 
    key, value
having 
    count(*) > 1

Answer 2

I f you need the id of all the rows for key,value count(= >1)

 select id from  `PROPERTY`
 where (key, value) in (select key, value from `PROPERTY`group by 
key, value
 having 
count(*) > 1)

Answer 3

鉴于更新的问题...

既然您知道具体的密钥，那么您也知道有多少密钥...所以有一个不同的计数应该这样做...以及在哪里......

SELECT id
FROM `PROPERTY`
Where key in ('foo','bar','foobar')
GROUP BY ID
having count(distinct key) = 3