我有一个大约168,200,000个文档的mongo db集合。我试图用$ group获取某个字段的平均值,并且我在管道中的$ group之前使用$ match来使用client.city上的索引。但查询运行大约需要5分钟,这非常慢。
以下是我尝试过的事情:
db.ar12.aggregate(
{$match:{'client.city':'New York'}},
{'$group':{'_id':'client.city', 'avg':{'$avg':'$length'}}}
)
db.ar12.aggregate(
{$match:{'client.city':'New York'}},
{'$group':{'_id':null, 'avg':{'$avg':'$length'}}}
)
db.ar12.aggregate(
{$match:{'client.city':'New York'}},
{$project: {'length':1}},
{'$group':{'_id':null, 'avg':{'$avg':'$length'}}}
)
所有3个查询大约需要同一时间,client.city =到纽约的文档数量为1,231,672,find({'client.city':'New York').count()
需要一秒钟才能运行
> db.version()
3.2.0
修改
这里是解释结果......对于添加长度的复合索引的注释,这会有所帮助,虽然我不是按长度搜索我想要所有长度......
{
"waitedMS" : NumberLong(0),
"stages" : [
{
"$cursor" : {
"query" : {
"client.city" : "New York"
},
"fields" : {
"length" : 1,
"_id" : 1
},
"queryPlanner" : {
"plannerVersion" : 1,
"namespace" : "clients.ar12",
"indexFilterSet" : false,
"parsedQuery" : {
"client.city" : {
"$eq" : "New York"
}
},
"winningPlan" : {
"stage" : "FETCH",
"inputStage" : {
"stage" : "IXSCAN",
"keyPattern" : {
"client.city" : 1
},
"indexName" : "client.city_1",
"isMultiKey" : false,
"isUnique" : false,
"isSparse" : false,
"isPartial" : false,
"indexVersion" : 1,
"direction" : "forward",
"indexBounds" : {
"client.city" : [
"[\"New York\", \"New York\"]"
]
}
}
},
"rejectedPlans" : [ ]
}
}
},
{
"$project" : {
"length" : true
}
},
{
"$group" : {
"_id" : {
"$const" : null
},
"total" : {
"$avg" : "$length"
}
}
}
],
"ok" : 1
}
编辑2
我已添加了client.city和length的复合索引,但无效但速度仍然太慢,我尝试了这两个查询:
db.ar12.aggregate(
{$match: {'client.city':'New York'}},
{$project: {'client.city':1, 'length':1}},
{'$group':{'_id':'$client.city', 'avg':{'$avg':'$length'}}}
)
上面的查询并没有使用复合索引,所以我尝试使用它来强制使用它,但仍然没有改变:
db.ar12.aggregate(
{$match: { $and : [{'client.city':'New York'}, {'length':{'$gt':0}}]}},
{$project: {'client.city':1, 'length':1}},
{'$group':{'_id':'$client.city', 'avg':{'$avg':'$length'}}}
)
下面是最后一个查询的解释:
{
"waitedMS" : NumberLong(0),
"stages" : [
{
"$cursor" : {
"query" : {
"$and" : [
{
"client.city" : "New York"
},
{
"length" : {
"$gt" : 0
}
}
]
},
"fields" : {
"client.city" : 1,
"length" : 1,
"_id" : 1
},
"queryPlanner" : {
"plannerVersion" : 1,
"namespace" : "clients.ar12",
"indexFilterSet" : false,
"parsedQuery" : {
"$and" : [
{
"client.city" : {
"$eq" : "New York"
}
},
{
"length" : {
"$gt" : 0
}
}
]
},
"winningPlan" : {
"stage" : "CACHED_PLAN",
"inputStage" : {
"stage" : "FETCH",
"inputStage" : {
"stage" : "IXSCAN",
"keyPattern" : {
"client.city" : 1,
"length" : 1
},
"indexName" : "client.city_1_length_1",
"isMultiKey" : false,
"isUnique" : false,
"isSparse" : false,
"isPartial" : false,
"indexVersion" : 1,
"direction" : "forward",
"indexBounds" : {
"client.city" : [
"[\"New York\", \"New York\"]"
],
"length" : [
"(0.0, inf.0]"
]
}
}
}
},
"rejectedPlans" : [ ]
}
}
},
{
"$project" : {
"client" : {
"city" : true
},
"length" : true
}
},
{
"$group" : {
"_id" : "$client.city",
"avg" : {
"$avg" : "$length"
}
}
}
],
"ok" : 1
}
答案 0 :(得分:0)
我找到了一个工作,长度从1到70.所以我所做的是在python中我从1到70迭代,并找到每个城市的每个长度的计数,
db.ar12.find({'client.city':'New York', 'length':i}).count()
这是非常快的,然后在python中计算平均值,运行大约需要2秒。
这不是最好的解决方案,因为我还有其他查询要运行,我不知道我是否可以为所有这些查找... ...