Question

我正在使用ZK 8 + Spring Security 4 + Spring Boot 1.3将应用程序（JDK 6，ZK 6.5，Spring Framework 3.2，Spring Security 3.1）升级到JDK 8，但我在上看到以下错误成功登录（即，如果用户名或密码不正确，我没有看到此错误）：

10:13:39.139 [http-nio-8080-exec-220] DEBUG o.z.zk.au.http.DHtmlUpdateServlet - Error found at client:
    [Receive]Unexpected token < (SyntaxError)     
    sid: 9524     
    user-agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36
    content-length: 309
    content-type: application/x-www-form-urlencoded;charset=UTF-8
    ip: 0:0:0:0:0:0:0:1

导致客户端上出现一个丑陋的基于ZK框架的弹出窗口。发生此错误时呈现的页面为/secure/login.zul，但tidy报告页面中没有错误：

tidy -xml ./src/main/webapp/secure/login.zul
No warnings or errors were found.

/secure/login.zul ：

<?xml version="1.0" encoding="UTF-8"?>
<?page title="Login"?>
<?init class="com.xxxxxx.web.OnlyAnonymousInitiator"?>
<zk xmlns="http://www.zkoss.org/2005/zul" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.zkoss.org/2005/zul http://www.zkoss.org/2005/zul/zul.xsd" xmlns:n="native" xmlns:h="http://www.w3.org/1999/xhtml"
    xmlns:w="client">
  <n:div class="container_16">
    <n:div class="grid_12">
      <idspace>
    <panel border="normal">
      <caption label="Login" />
      <panelchildren apply="com.xxxx.web.pages.login.LoginMainComposer">
        <n:div class="xxxxxx-panel-contents">
          <n:table class="xxxxxx-table-plain">
        <n:tr>
          <n:td>
            <label value="Username:" />
          </n:td>
          <n:td>
            <textbox id="username" />
          </n:td>
        </n:tr>
        <n:tr>
          <n:td>
            <label value="Password:" />
          </n:td>
          <n:td>
            <textbox id="password" type="password" />
          </n:td>
        </n:tr>
        <n:tr>
          <n:td />
          <n:td>
            <button id="login" label="Log in" image="/images/icons/door_in.png" />
          </n:td>
        </n:tr>
          </n:table>
          <button href="/" label="Cancel" image="/images/icons/cross.png" />
        </n:div>
      </panelchildren>
    </panel>
      </idspace>
    </n:div>
  </n:div>
</zk>

，此页面在原始应用程序中正常工作。 zk.xml文件非常简单：

<?xml version="1.0" encoding="UTF-8"?>
<zk>
  <desktop-config>
    <theme-uri>/css/960.css</theme-uri>
    <theme-uri>/css/xxxxxx.css</theme-uri>
  </desktop-config>
  <system-config>
    <ui-factory-class>
      com.xxxxxx.web.XxxxxxUiFactory
    </ui-factory-class>
  </system-config>
  <device-config>
    <device-type>ajax</device-type>
    <server-push-class>
      fi.gekkio.splake.atmosphere.AtmosphereServerPush
    </server-push-class>
  </device-config>
  <library-property>
    <name>org.zkoss.theme.preferred</name>
    <value>atlantic</value>
  </library-property>
  <library-property>
    <name>org.zkoss.bind.DebuggerFactory.enable</name>
    <value>true</value>
  </library-property>
</zk>

知道这个错误的根源是什么？或者如何从ZK获取更多信息进行调试？或者如何解决？

Reviewing code ZK framework code，我明白了：

final String errClient = request.getHeader("ZK-Error-Report");
        if (errClient != null)
            if (log.isDebugEnabled()) 
                log.debug(
                    "Error found at client:
                        "+errClient+"\n"+Servlets.getDetail(request));

并查看响应标头，我看到：

Referer:http://localhost:8080/xxxxxx/secure/login.zul
User-Agent:Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36
ZK-Error-Report:[Receive] Unexpected token < (SyntaxError)
ZK-SID:1111

以及以下响应标头：

ZK-Error:410
ZK-SID:1111

（SID与原版不同但错误相同......）在Chrome中，我会在触发错误时看到两个请求：

Request URL:http://localhost:8080/xxxxxx/zkau
Request Method:POST
Status Code:302 Found
Remote Address:[::1]:8080
Response Headers
view source

接下来是：

Request URL:http://localhost:8080/xxxxxx/
Request Method:GET
Status Code:200 OK
Remote Address:[::1]:8080

所以看起来很可能，上面的302（错误）处理会以某种方式触发此错误消息。

Answer 1

呃 - 非常沮丧。

在ZK内花了很多时间试图追踪这个问题而没有找到可行的解决方案后，我放弃了;我已经用Spring Boot，Spring Security和Angular 2取代了ZK，我现在正在取得进展。

DHtmlUpdateServlet - 在客户端发现错误：[Receive]意外的令牌＆lt; （的SyntaxError）

1 个答案: