它无效。我在尝试如下。
$(document).ready(function() {
$('#circle').hover(
function() { // mouseenter event equivalent in hover
$('#intro').hide([2]);
},
function() { // mouseleave event equivalent in hover
$('#intro').show([2]);
});
});
以下是完整的代码段。
if (($row["steamid"]) == $steamprofile['steamid']){
我尝试了各种方法。
答案 0 :(得分:0)
// Create connection
$conn = new mysqli("localhost", "root", "", "stackoverflow");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//assume 1
$steamprofile['steamid']=1;
// changes here single quote
$eh = $steamprofile['steamid'];
$sql = "SELECT steamid FROM Main";
$result = $conn->query($sql);
if ($result->num_rows > 0)
{
// output data of each row
while($row = $result->fetch_assoc())
{
if (($row["steamid"]) == $steamprofile['steamid']){
echo "SteamID Is Equal and Created!";
}
}
} else {
echo "Nope?";
}
$conn->close();
?>
输出是 SteamID是平等和创造的!
Mysql数据库------------
CREATE TABLE IF NOT NOT EXISTS main
(
steamid
int(11)NOT NULL,
name
varchar(500)NOT NULL
)ENGINE = InnoDB AUTO_INCREMENT = 3 DEFAULT CHARSET = latin1;
-
main
INSERT INTO main
(steamid
,name
)VALUES
(1,' test1'),
(2,' test2');
答案 1 :(得分:0)
我认为你的
$eh = $steamprofile[steamid];
应改为
$eh = $steamprofile['steamid'];
答案 2 :(得分:0)
评论:
尝试echo $ row [" steamid"])。" =="。 $ steamprofile [' steamid'];所以你可以打印并检查。 - Hardy Mathew
的工作。感谢。