Question

let url = NSURL(string: urlString)

let theRequest = NSMutableURLRequest(URL: url!)

theRequest.HTTPMethod = "POST"

let parameters = ["userId":userId.text!,"status":"offline"] as Dictionary<String,String>


var err:NSError!

do{

    theRequest.HTTPBody = try NSJSONSerialization.dataWithJSONObject(parameters, options: [])
}

catch let error as NSError
{
    err = error
    theRequest.HTTPBody = nil
}

theRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
theRequest.addValue("application/json", forHTTPHeaderField: "Accept")

如何将开关控制参数传递给服务器？

Answer 1

传递bool的值，你需要将它作为另一个参数传递给函数。例如，现在你有：

let url = NSURL(string: urlString)

将其更改为：

 let url = NSURL(string: urlString, value1: Bool)

然后，当您从视图控制器调用此post函数时，您需要获取与该开关值对应的bool值的当前状态。你可以这样做：

let value = yourBool.boolValue()

然后，在你的帖子功能中，做一下这样的事情：

  let url = NSURL(string: urlString, value1: Bool)
  var status = String()
  if value1 == true {
  status = "online"
  }
  else {

  status = "offline"

  }

 let theRequest = NSMutableURLRequest(URL: url!)

 let parameters = ["userId":userId.text!,"status":status]

如何以编程方式将swift控制器的参数传递给服务器？

1 个答案: