Question

我有一个原始的“条目”和“退出”数据作为json for person（按日期排序）。

[{
   id: 1,
   dateTime: "2015-11-26T16:30:48.000Z",
   gateNumber: "192.168.0.202",
   gateType: "entry",
   personId: 207
}, // the exit object is missing for id=1. I need to create same object as exit vice versa...
{
   id: 2,
   dateTime: "2015-11-26T16:35:44.000Z",
   gateNumber: "192.168.0.201",
   gateType: "entry",
   personId: 207
}, {
   id: 3,
   dateTime: "2015-11-26T16:36:40.000Z",
   gateNumber: "192.168.0.202",
   gateType: "exit",
   personId: 207
}, {
   id: 4,
   dateTime: "2015-11-26T16:37:22.000Z",
   gateNumber: "192.168.0.201",
   gateType: "entry",
   personId: 207
}, {
   id: 5,
   dateTime: "2015-11-26T16:38:55.000Z",
   gateNumber: "192.168.0.201",
   gateType: "exit",
   personId: 207
}]

它需要像入门一样 - ＆gt;退出 - ＆gt;进入 - ＆gt;出口。但有时会丢失一些“退出”或某些“入口”对象。

所以我试图检测丢失的“对象”并为批量插入创建一个数组，因为差异将是0秒并且会失败。

所以，解决方案应该适用于以上情况;

[
   [1, "2015-11-26T16:30:48.000Z", "192.168.0.202", "exit", 207], 
   //... if there are any more..
]

Answer 1

var json_obj = [{
   id: 1,
   dateTime: "2015-11-26T16:30:48.000Z",
   gateNumber: "192.168.0.202",
   gateType: "entry",
   personId: 207
},
{
   id: 2,
   dateTime: "2015-11-26T16:35:44.000Z",
   gateNumber: "192.168.0.201",
   gateType: "entry",
   personId: 207
}, {
   id: 3,
   dateTime: "2015-11-26T16:36:40.000Z",
   gateNumber: "192.168.0.202",
   gateType: "exit",
   personId: 207
}, {
   id: 4,
   dateTime: "2015-11-26T16:37:22.000Z",
   gateNumber: "192.168.0.201",
   gateType: "entry",
   personId: 207
}, {
   id: 5,
   dateTime: "2015-11-26T16:38:55.000Z",
   gateNumber: "192.168.0.201",
   gateType: "exit",
   personId: 207
}];


your_new_array = json_obj.map(function(obj){
  if(!obj.hasOwnProperty('exit'))
     {
       obj.exit = 'exit value';
     }
  if(!obj.hasOwnProperty('entry'))
     {
       obj.entry = 'entry value';
     }
    return obj;
});
console.log(your_new_array);

https://jsfiddle.net/4f5Lpcge/小提琴:)我希望它有所帮助！

Json数组构建

1 个答案: