代码很好,但在控制台坏参数中得到错误

时间:2016-01-14 07:12:37

标签: angularjs twitter-bootstrap

我是新的角度我试图通过下拉列表代码显示安全问题,当它是单页但是当它在那时添加到.js文件时显示

<div class="container re" ng-controller="securityQuestionController">
    <div class="row">
        <h2>Set your Security Question</h2>
        <h3>To keep your account protected please set your own security question</h3>  
        <div class="col-lg-4">
            <form action="">
                <label for="peopleArraySel1">Array select 2:</label>
                <select class="form-control" ng-options="p.first for p in people" ng-model="selectedPerson">
                </select>
            </form>
        </div>
    </div>

    app.controller("securityQuestionController",function($scope){
        $scope.people = [
            {'first': 'what is your school name'},
            {'first': 'what is collage name'},
            {'first': 'what is your father name'}
        ];
    });

我的代码

const int aSel = 40;
UINT MyVar= aSel - strlen( Mystring );//Warning C4267

0 个答案:

没有答案