Question

我的模型看起来像这样简化了

@Table
public class Movie extends SugarRecord implements Parcelable {

@SerializedName("id")
@Expose
private Long movieId;
@SerializedName("adult")
@Expose
private Boolean adult;
@SerializedName("backdrop_path")
@Expose
private String backdropPath;
@SerializedName("genre_ids")
@Expose
private List<Integer> genreIds = new ArrayList<>();
@SerializedName("original_language")
@Expose
private String originalLanguage;
@SerializedName("original_title")
@Expose
private String originalTitle;
@SerializedName("overview")
@Expose
private String overview;
@SerializedName("release_date")
@Expose
private String releaseDate;
@SerializedName("poster_path")
@Expose
private String posterPath;
@SerializedName("popularity")
@Expose
private Double popularity;
@SerializedName("title")
@Expose
private String title;
@SerializedName("video")
@Expose
private Boolean video;
@SerializedName("vote_average")
@Expose
private Double voteAverage;
@SerializedName("vote_count")
@Expose
private Integer voteCount;

private Boolean favourite;


public Movie() {
    this.favourite = false;
}

public static final Parcelable.Creator CREATOR = new Parcelable.Creator() {
    public Movie createFromParcel(Parcel in) {
        return new Movie(in);
    }

    public Movie[] newArray(int size) {
        return new Movie[size];
    }
};

public Movie(Parcel in) {
    this.adult = in.readByte() != 0;
    this.movieId = in.readLong();
    this.backdropPath = in.readString();
    in.readList(this.genreIds, null);
    this.originalLanguage = in.readString();
    this.originalTitle = in.readString();
    this.overview = in.readString();
    this.releaseDate = in.readString();
    this.posterPath = in.readString();
    this.popularity = in.readDouble();
    this.title = in.readString();
    this.video = in.readByte() != 0;
    this.voteAverage = in.readDouble();
    this.voteCount = in.readInt();
    this.favourite = in.readByte() != 0;
}

@Override
public int describeContents() {
    return 0;
}

@Override
public void writeToParcel(Parcel dest, int flags) {
    dest.writeByte((byte) (this.adult ? 1 : 0));
    dest.writeLong(this.movieId);
    dest.writeString(this.backdropPath);
    dest.writeList(this.genreIds);
    dest.writeString(this.originalLanguage);
    dest.writeString(this.originalTitle);
    dest.writeString(this.overview);
    dest.writeString(this.releaseDate);
    dest.writeString(this.posterPath);
    dest.writeDouble(this.popularity);
    dest.writeString(this.title);
    dest.writeByte((byte) (this.video ? 1 : 0));
    dest.writeDouble(this.voteAverage);
    dest.writeInt(this.voteCount);
    dest.writeByte((byte) (this.favourite ? 1 : 0));
}
}

错误消息我在Gson尝试转换从改造中收到的结果时得到。

java.lang.IllegalArgumentException: class Movie declares multiple JSON fields named id

当Movie没有扩展SugarRecord时，它完全正常。

我可以在这做什么？

Answer 1

不要同时使用@Table并扩展SugarRecord（至少不在SugarORM 1.4中）。

Please check my answer here.

Answer 2

如果您只想考虑标记为@Expose的字段，则需要致电：

Gson gson = new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

此处有更多信息：http://www.javacreed.com/gson-annotations-example/

Answer 3

声明私有瞬态Long id。

这样，你的id字段就不会被序列化。

与糖orm和gson冲突

3 个答案: