我有一个ng-repeat过滤参数 city & first_name ,如示例所示:
vm.search = {
"city": "D.C.",
"first_name": "Chu"
};
<li ng-repeat="item in user | filter: search">...
var appname = 'app';
var dependencies = [];
angular.module(appname, dependencies);
var app = angular.module(appname);
var userC = function ($scope) {
var vm = $scope;
vm.search = {
"city": "D.C.",
"first_name": "Chu"
};
vm.user = [
{
"id": 1,
"first_name": "Chuck",
"last_name": "Norris",
"city": "Washington D.C.",
"languages": [
{
"id": "41",
"name": "English"
},
{
"id": "73",
"name": "Japanese"
}
]
}
];
};
app.controller('userC', userC);
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<ul ng-app="app" ng-controller="userC">
<li ng-repeat="item in user | filter: search track by item.id">
{{ item.first_name }} {{ item.last_name }}
</li>
</ul>
&#13;
但现在我需要按语言进行过滤,这是一个对象数组:
vm.search = {
"languages": [
{
"name": "Japanese"
}
]
};
<li ng-repeat="item in user | filter: search">...
var appname = 'app';
var dependencies = [];
angular.module(appname, dependencies);
var app = angular.module(appname);
var userC = function ($scope) {
var vm = $scope;
vm.search = {
"languages": [
{
"name": "Japanese"
}
]
};
vm.user = [
{
"id": 1,
"first_name": "Chuck",
"last_name": "Norris",
"city": "Washington D.C.",
"languages": [
{
"id": "41",
"name": "English"
},
{
"id": "73",
"name": "Japanese"
}
]
}
];
};
app.controller('userC', userC);
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<ul ng-app="app" ng-controller="userC">
<li ng-repeat="item in user | filter: search track by item.id">
{{ item.first_name }} {{ item.last_name }}
</li>
</ul>
&#13;
正如您所看到的,没有结果,因为默认的过滤器无法完成这项工作。
有人可以帮我找到适合这种情况的过滤器吗?
这两个例子都在这里:
答案 0 :(得分:1)
您必须将languages
声明为对象:
vm.search = {
"languages":
{
"name": "Japanese"
}
};
Here's代码。
评论后更新:如果您想要更复杂的过滤器,可以使用函数而不是对象。 Angular会在user
数组上调用Array.prototype.filter(),因此可以通过以下方式定义函数:
var allowedLanguages = [
"Japanese",
"Brazilian Portuguese"
];
vm.search = function(item) {
for (var i = 0; i < item.languages.length; i++) {
if (allowedLanguages.indexOf(item.languages[i].name) !== -1) {
return true;
}
}
return false;
};