Question

我有一个看起来像这样的表：

在查询中，我需要找到两个时间段（行）上发生的最大导入值，其中值大于定义的阈值并应用速率。如果它发生超过两个时间段，将使用不同的速率

    WITH CTE AS (  

SELECT LogTable.[LocalTimestamp] as thetime,LogTable.[SystemImport] as import, LogTable.[Id] - ROW_NUMBER() OVER (ORDER BY LogTable.[Id]) AS grp
  FROM {System_KWLogRaw} LogTable
  WHERE LogTable.[SystemImport] between @DemandThreshold and @In1 and 
    DATEPART(year,@inDate) = DATEPART(year, LogTable.[LocalTimestamp]) and
    DATEPART(month,@inDate) = DATEPART(month, LogTable.[LocalTimestamp]) and
    DATEPART(day,@inDate) = DATEPART(day, LogTable.[LocalTimestamp])
),

counted AS (
    SELECT *, COUNT(*) OVER (PARTITION BY grp) AS cnt
    FROM CTE

    )

SELECT MAX(counted.import) as again1
FROM counted
WHERE cnt > 3 and counted.import < (SELECT MAX(counted.import) FROM counted)

Ids 2和3>阈值，因此查询应返回那些（2500,1900）= 1900减去阈值（1000）= 900的MIN值。应用率Rate1 * 900 = 9000

如果我们将Id 4的值更改为1200，则MIN值将为1200.减去阈值= 200. 200 * Rate2 = 4000

非常感谢任何帮助！

反馈后更新。我的挑战似乎是我没有抓住第二高的价值。以下是数据集的示例： Dataset example

我添加了另一个var来缩小列表以测试间隙和岛屿部分。这是一个较小的子集： Subset

以下是代码：

{{1}}

这将返回3555.53而不是3543.2，这是第二高的值

Answer 1

这将满足您的要求：

with x as (
select
t1.Id,
t1.DateTime,
t1.Import,
t1.Export,
t1.Total,
count(t2.Import) over (partition by 1) as [QualifyingImports],
min(t2.Import) over (partition by 1) as [MinQualifyingImport]

from
myTable t1
left join myTable t2 on t2.Import > 1000 and t2.Id = t1.Id

where
t1.DateTime >= '2016-01-13'
and t1.DateTime < dateadd(d, 1,'2016-01-13')

)

select
x.Id,
x.DateTime,
x.Import,
x.Export,
x.Total,
case when x.[QualifyingImports] > 2 then (x.MinQualifyingImport - 1000) * 200 else (x.MinQualifyingImport - 1000) * 100 end as [Rate]
from x

我已经整理了一个Fiddle，因此你可以为Id＃4使用不同的值。

我真的想把阈值和句点之类的值设置为@variables，但它似乎不支持CTE，所以我只需要对它们进行硬编码。

修改

原来CTE太过分了，你可以把它缩小到这个并使用@variables，耶！

declare @period smalldatetime = '2016-01-13' declare @threshold float = 1000 declare @rate1 float = 100 declare @rate2 float = 200 select t1.Id, t1.DateTime, t1.Import, t1.Export, t1.Total, case when count(t2.Import) over (partition by 1) > 2 then (min(t2.Import) over (partition by 1) - @threshold) * @rate2 else (min(t2.Import) over (partition by 1) - @threshold) * @rate1 end as [Rate] from myTable t1 left join myTable t2 on t2.Import > @threshold and t2.Id = t1.Id where t1.DateTime >= @period and t1.DateTime < dateadd(d, 1, @period)

新Fiddle

如果值在连续的时间段内发生，则SQL需要应用可变速率

非常感谢任何帮助！

1 个答案: