我有以下内容:
Lines <- "D1,Diff
1,20/11/2014 16:00,0.01
2,20/11/2014 17:00,0.02
3,20/11/2014 18:00,0.03
4,21/11/2014 16:00,0.04
5,21/11/2014 17:00,0.06
6,21/11/2014 18:00,0.07"
z <- read.zoo(text = Lines, tz = "", format = "%d/%m/%Y %H:%M", sep = ",")
ep <- endpoints(z,'hours')
a<-period.apply(z,ep,mean)
我想创建一个新的Zoo对象,每小时将有相同小时的Diff的平均值。所需的结果将是:
16:00,0.025
17:00,0.03
18:00,0.05
a的内容:
> a
2014-11-20 16:00:00 2014-11-20 17:00:00 2014-11-20 18:00:00 2014-11-21 16:00:00 2014-11-21 17:00:00 2014-11-21 18:00:00
0.01 0.02 0.03 0.04 0.06 0.07
答案 0 :(得分:0)
两种方式:
Zoo对象:
b&lt; -aggregate(z,hour(index(z)),mean) b 16 17 18 0.025 0.040 0.050 (b)类 [1]&#34;动物园&#34;
转换为数据帧:
a&lt; -aggregate(z~小时(指数(z)),FUN =&#39;意思是&#39;) 一个 小时(指数(z))z 1 16 0.025 2 17 0.040 3 18 0.050 上课(一) [1]&#34; data.frame&#34;