Question

我创建了一个简单的计算器，在其中我在两个不同的文本字段中输入两个操作数，并且它运行良好。但是我需要从同一个文本域中获取两个输入。我应该做些什么改变？

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;

class Calculation_ActionEvent extends JFrame implements ActionListener
{
    JFrame f;
    JLabel l;
    JTextField tf1, tf2, tf3;
    JButton b1, b2, b3, b4 ,b5, b6;
    Calculation_ActionEvent(String s)
    {
        f = new JFrame("Calculation");
        f.setLayout(null);
        l = new JLabel("Enter two numbers : ");
        tf1 = new JTextField();
        tf2 = new JTextField();
        tf3 = new JTextField();
        b1 = new JButton("+");
        b2 = new JButton("-");
        b3 = new JButton("*");
        b4 = new JButton("/");
        b5 = new JButton("equals");
        b6 = new JButton("C");
        f.add(l);
        f.add(tf1);
        f.add(tf2);
        f.add(tf3);
        f.add(b1);
        f.add(b2);
        f.add(b3);
        f.add(b4);
        f.add(b5);
        f.add(b6);
        tf1.setBounds(180,100,50,30);
        tf2.setBounds(320,100,50,30);
        tf3.setBounds(250,420,50,30);
        b1.setBounds(250,180,50,30);
        b2.setBounds(350,260,50,30);
        b3.setBounds(150,260,50,30);
        b4.setBounds(250,340,50,30);
        b5.setBounds(230,260,90,30);
        b6.setBounds(250,100,50,30);
        b1.addActionListener(this);
        b2.addActionListener(this);
        b3.addActionListener(this);
        b4.addActionListener(this);
      //b5.addActionListener(this);
        b6.addActionListener(this);
        f.setSize(550,550);
        f.setVisible(true);
    }

    public void actionPerformed(ActionEvent e)
    {
        int num1= Integer.parseInt(tf1.getText());
        int num2= Integer.parseInt(tf2.getText());
        String s1 = e.getActionCommand();
        if(s1.equals("C"))
        {
            tf1.setText("0");
            tf2.setText("0");
            tf3.setText("0");
        }
        else
        {
         if(s1=="+")
        {
            tf3.setText(String.valueOf(num1+num2)); 
        }
        if(s1=="-")
        {
            tf3.setText(String.valueOf(num1-num2)); 
        }
        if(s1=="*")
        {
            tf3.setText(String.valueOf(num1*num2)); 
        }
        if(s1=="/")
        {
            tf3.setText(String.valueOf(num1/num2)); 
        }
        }
 }

    public static void main(String... s)
    {
        new Calculation_ActionEvent("Calculation");
    }
 }

Answer 1

只需从两个文本框中获取值并执行所有计算加法，乘法，减法，除法和存储在不同的变量中，并在文本框中设置该变量，您无法直接在textbox.ex中执行操作

String val1=textbox1.gettext();
String val2=textbox2.gettext();
int addition=Integer.ParseInt(val1)+Integer.ParseInt(val2);
textbox3.settext(addition.toString());

Answer 2

这会是你想要的吗？我为你做了一个快速版本。

简单地说，我将最后一个运算符（+，-，*，/）存储在String变量中lastAction ），total为int。当＆＃34;等于＆＃34;按下，我计算总数并重置total变量和lastAction。按下操作符时，我会更改总数，但将最后一个值保留在变量中。

package cf.pgmann.calc;

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JTextField;

class Calculation_ActionEvent extends JFrame implements ActionListener {
    JFrame f;
    JLabel l;
    JTextField tf1, tf3;
    JButton b1, b2, b3, b4, b5, b6;

    Calculation_ActionEvent(String s) {
        f = new JFrame(s);
        f.setLayout(null);
        l = new JLabel("Enter two numbers : ");
        tf1 = new JTextField();
        // tf2 = new JTextField();
        tf3 = new JTextField();
        b1 = new JButton("+");
        b2 = new JButton("-");
        b3 = new JButton("*");
        b4 = new JButton("/");
        b5 = new JButton("equals");
        b6 = new JButton("C");
        f.add(l);
        f.add(tf1);
        f.add(tf3);
        f.add(b1);
        f.add(b2);
        f.add(b3);
        f.add(b4);
        f.add(b5);
        f.add(b6);
        tf1.setBounds(160, 100, 250, 30);
        // tf2.setBounds(320,100,50,30);
        tf3.setBounds(250, 420, 50, 30);
        b1.setBounds(250, 180, 50, 30);
        b2.setBounds(350, 260, 50, 30);
        b3.setBounds(150, 260, 50, 30);
        b4.setBounds(250, 340, 50, 30);
        b5.setBounds(230, 260, 90, 30);
        b6.setBounds(420, 100, 50, 30);
        b1.addActionListener(this);
        b2.addActionListener(this);
        b3.addActionListener(this);
        b4.addActionListener(this);
        b5.addActionListener(this);
        b6.addActionListener(this);
        f.setSize(550, 550);
        f.setVisible(true);
    }

    int total = 0;
    String lastAction = "";

    public void actionPerformed(ActionEvent e) {
        int num = 0;
        try {
            num = Integer.parseInt(tf1.getText());
        } catch(NumberFormatException ex) {}
        String s1 = e.getActionCommand();
        if (s1.equals("C")) {
            tf1.setText("");
            tf3.setText("0");
            tf1.requestFocus();
            total = 0;
        } else if (s1.equals("equals")) {
            tf3.setText(String.valueOf(calc(total, lastAction, num)));
            tf1.setText("");
            tf1.requestFocus();
            total = 0;
        } else {
            total = total==0 ? num : calc(total, lastAction, num);
            tf3.setText(String.valueOf(total));
            tf1.setText("");
            tf1.requestFocus();
            lastAction = s1;
        }
    }

    private int calc(int num1, String action, int num2) {
        switch (action) {
        case "+":
            return num1 + num2;
        case "-":
            return num1 - num2;
        case "*":
            return num1 * num2;
        case "/":
            return num1 / num2;
        default:
            return num1;
        }
    }

    public static void main(String... s) {
        new Calculation_ActionEvent("Calculator");
    }
}

如何在AWT / SWING中输入来自同一文本字段的两位数字

2 个答案: