我正在使用IntentService
实现基于聊天的应用。现在我需要获取消息,即使应用程序不在后台。显然我想要的是如果应用程序不处于后台状态,我需要运行intent服务。
public class ChatService extends IntentService {
JabberSmackAPI c = null;
XMPPConnection connection;
@Override
public void onCreate() {
super.onCreate();
System.out.println("chatservice------onCreate-----");
}
@Override
public int onHandleIntent(Intent arg0) {
System.out.println("--chat services--");
try {
setUp(c);
} catch (XMPPException e) {
// TODO Auto-generated catch block
System.out.println("--XMPPConnection error--chat service--");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
System.out.println("--IOException error--chat service--");
e.printStackTrace();
}
return super.onStartCommand(intent, flags, startId);
}
@Nullable
@Override
public IBinder onBind(Intent intent) {
return null;
}
private void setUp(JabberSmackAPI c) throws XMPPException, IOException {
// declare variables
c = new JabberSmackAPI();
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String msg = "hi how r u!";
// Enter your login information here
c.login(chat_id, GlobalDeclaration.paswword);
System.out.println("-----");
String talkTo = "username";
}
public class JabberSmackAPI implements MessageListener, ChatManagerListener {
public void login(String userName, String password) throws XMPPException {
ConnectionConfiguration config = new ConnectionConfiguration("Host", 5222);
connection = new XMPPConnection(config);
connection.connect();
PacketFilter filter = new MessageTypeFilter(Message.Type.chat);
connection.addPacketListener(packetListener, filter);
connection.login(userName, password);
}
}
private PacketListener packetListener = new PacketListener() {
public void processPacket(Packet packet) {
// TODO Auto-generated method stub
System.out.println("In the process packet");
System.out.println(packet.toXML());
Intent broadcastIntent = new Intent();
broadcastIntent.setAction("FILE_DOWNLOADED_ACTION");
getBaseContext().sendBroadcast(broadcastIntent);
System.out.println("---final packrt result-- " + packectResult.trim());
}
};
}
答案 0 :(得分:1)
您可以每隔X次添加一次警报,此警报可以触发服务。
解决方案1:闹钟 - 通话 - > BroadcastReceiver - Fire(开始) - >你的服务。
解决方案2:任何系统BroadcastReceiver(例如电池电平变化) - >你的服务。
-----更新-------
public class BaseNotificationManager extends BroadcastReceiver {
public static final String BaseAction = "Com.TST.BaseAction";
public static final String FireService = "Com.TST.FireNotificationAction";
private static final long timeFrame = 1000*60*5; // 5 mints
public BaseNotificationManager() {
}
@Override
public void onReceive(Context context, Intent intent) {
if (Intent.ACTION_BOOT_COMPLETED.equals(intent.getAction())) {
/// add base alarm manager
startBaseAlarmManager(context);
}else if (BaseAction.equals(intent.getAction())){
// StartYourService();
}
} public static void startBaseAlarmManager (Context context){
AlarmManager alarmMgr;
PendingIntent alarmIntent;
alarmMgr = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(context, BaseNotificationManager.class);
intent.setAction(BaseAction);
alarmIntent = PendingIntent.getBroadcast(context, 0, intent, 0);
alarmMgr.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP,
5000, timeFrame, alarmIntent);
}}
清单
<receiver
android:name=".BaseNotificationManager"
android:enabled="true"
android:exported="true">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
答案 1 :(得分:0)
基本上service
正在您的背景中运行,即使您的应用已被杀死。
只需将服务称为
即可 Intent chatService = new Intent(MainActivity.this,ChatService.class);
startService(chatService);
答案 2 :(得分:0)
你应该startService和bindService
如果您只使用bindService,那么一旦您离开该类,它将被终止。
StartService将使您的服务保持活力。
如下:
Intent intentService = new Intent(MainActivity.this, MyService.class);
startService(intentService);
bindService(new Intent(MainActivity.this, MyService.class),MainActivity.this, BIND_AUTO_CREATE);
答案 3 :(得分:0)
尝试在onStartCommand中添加startForeground,它将提高服务的优先级。但它应该伴随着通知存在。
startForeground(int id, Notification notification)