Question

如何选择和排序以LIKE 'a%开头的所有结果，然后包含LIKE '%a%'的限制，例如3。

例如以下数据集：b，aab，baa，cad，ccc，bb，ac。期望的结果是得到aab，ac，baa。（如果限制为2，则不应返回包含项目。）

Answer 1

在您的具体案例中，这有效：

SELECT Column1
FROM table1
WHERE (Column1 LIKE 'a%' OR Column1 LIKE '%a%')
ORDER BY Column1
LIMIT 3

以下情况应该有效，请将table1和Column1替换为真实姓名，然后尝试Limit 2和Limit 3。当a也可以yourcustomstring时，此案例非常有用：

SELECT Column1
FROM (
    SELECT Column1 
    FROM table1
    WHERE Column1 LIKE 'a%'
    ORDER BY Column1
) T1
UNION 
SELECT Column1 FROM 
(
    SELECT Column1 
    FROM table1
    WHERE Column1 LIKE '%a%'
    ORDER BY Column1
) T2
LIMIT 3

工作示例：

SELECT *
    FROM (
        SELECT YourTableAsUnion.Column1
        FROM (SELECT 'b' AS Column1
        UNION 
        SELECT 'aab'
        UNION
        SELECT 'baa'
        UNION 
        SELECT 'cad'
        UNION 
        SELECT 'ccc'
        UNION 
        SELECT 'bb'
        UNION
        SELECT 'ac'
        ) YourTableAsUnion
        WHERE YourTableAsUnion.Column1 LIKE 'a%'
        ORDER BY YourTableAsUnion.Column1
    ) T1
    UNION SELECT * FROM (
        SELECT YourTableAsUnion.Column1
        FROM (SELECT 'b' AS Column1
        UNION 
        SELECT 'aab'
        UNION
        SELECT 'baa'
        UNION 
        SELECT 'cad'
        UNION 
        SELECT 'ccc'
        UNION 
        SELECT 'bb'
        UNION
        SELECT 'ac'
        ) YourTableAsUnion
        WHERE YourTableAsUnion.Column1 LIKE '%a%'
        ORDER BY YourTableAsUnion.Column1
    ) T2
    LIMIT 3

Mysql查询顺序以包含然后开始

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