Question

我有一个String，它可以包含以下两种时间格式中的任何一种：

1:46 PM
（2:49:02 PM）

我想使用正则表达式在java中拆分此字符串。

例如： String str="hello ram, you logged in at1:46 PM we welcome you. Hello ram you logged out at(2:49:02 PM) see you again."

使用split使用regex的预期输出应为：

hello ram, you logged in at

1:46 PM we welcome you. Hello ram you logged out at

(2:49:02 PM) see you again.

在这种情况下我应该使用什么正则表达式。我希望在新行中以两种时间格式分割文本。指导我。

Answer 1

你可以想出类似的东西：

(?<tsp>\d+(?::\d+)+)\s[AP]M
# Looks for a digit (minimum 1)
# followed by at least one (or multiple pairs) of ":" and another digit
# this pattern is captured in a named group called tsp
# ... which in turn is followed by a whitespace and "AM" or "PM"

查看demo on regex101。

Answer 2

您可以在Java中使用它：

Pattern p = Pattern.compile(
  "(?im)((?:^|\\(?\\d+(?::\\d+)+\\s+[AP]M\\)?).*?)(?=\\(?\\d+(?::\\d+)+\\s+[AP]M\\)?|$)");

Matcher m = p.matcher(input);

while (m.find() {
   System.out.println(m.group(1));
}

RegEx Demo

<强>输出

hello ram, you logged in at
1:46 PM we welcome you. Hello ram you logged out at
(2:49:02 PM) see you again.

Answer 3

此正则表达式根据需要拆分输入：

(?=\(\d\d?:\d\d:\d\d [AP]M\)|\d\d?:\d\d [AP]M [^)])

请参阅live regex demo。

一些测试代码：

public static void main (String[] args) {
    String str="hello ram, you logged in at1:46 PM we welcome you. Hello ram you logged out at(2:49:02 PM) see you again.";
    Arrays.stream(str.split("(?=\\(\\d\\d?:\\d\\d:\\d\\d [AP]M\\)|\\d\\d?:\\d\\d [AP]M [^)])")).forEach(System.out::println);
}

输出：

hello ram, you logged in at
1:46 PM we welcome you. Hello ram you logged out at
(2:49:02 PM) see you again.

在java中使用正则表达式为时间格式拆分字符串

3 个答案: