我有自己的web应用程序，使用laravel作为后端，工作正常。
现在，我开始编写IOS应用程序（IOS 9，Xcode 7，Swift 2），并希望将其连接到我的Web应用程序数据库，以便我可以使用API进行查询。
我遇到的第一步是用户通过IOS应用程序连接到Web应用程序数据库的登录名/密码。
我已在我的网络应用上安装了oauth 2.0配置并使用密码授予类型。使用Postman测试，我可以使用x-www-form-urlencoded中的以下参数获取访问令牌：
现在，我想使用IOS应用程序中的这些凭据访问此Web应用程序的数据库。
我在视图控制器中创建了一个登录表单。当我点击登录按钮时，我按如下方式启动IBAction：
@IBAction func login(sender: UIButton){
let myURL = NSURL(string: "http://myWebApplication.com/oauth/access_token")!
let request = NSMutableURLRequest(URL: myURL)
request.HTTPMethod = "POST"
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
let bodyStr:String = "grant_type=password&client_id=f3d259ddd3ed8ff3843839b&client_secret=4c7f6f8fa93d59c45502c0ae8c4a95b&username=user1@test.com&password=123456"
request.HTTPBody = bodyStr.dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
data, response, error in
// Your completion handler code here
}
task.resume()
}
但什么都没发生。
你可以告诉我我哪里错了吗？我花了几个小时搜索解决方案，上面的代码是此搜索的结果。不幸的是，还不够。
最重要的是，存储Web应用程序将返回并使用它的访问令牌的下一步是什么，以便我可以发送与此特定用户相关的查询？
提前感谢您的帮助
答案 0 :(得分：1)
我遇到了同样的问题..主要来自Cristina Moulton的iOS with REST API一书，希望它有所帮助。
试试这个：＃使用Alamofire＆amp; SwiftyJSON＃
func loginUser() {
var code:String?
var accessToken:String?
let path:String = EndPoints.kRestEndpoint + EndPoints.kToken
let parameters:[String:String] = ["grant_type": "password","client_id": "tes5@test.com.br", "client_secret": "123456"]
let headers:[String:String] = ["Content-Type": "application/x-www-form-urlencoded","Accept": "application/json"]
Alamofire.request(.POST, path, parameters: parameters, encoding: .URL, headers: headers).responseString { response in
// Handle response to extract the OAuth Token
if let error = response.result.error {
print(error)
return
}
// The access token + type
print(response.result.value)
if let receivedResults = response.result.value, jsonData = receivedResults.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false) {
let jsonResults = JSON(data: jsonData)
for (key, value) in jsonResults {
switch key {
case "access_token":
if let token = value.string {
code = token
}
case "token_type":
if let type = value.string {
accessToken = "\(type) \(code!)"
}
case "expires_in":
// Handle expiration
print("It has expiration")
default:
print("got more than I expected from the OAuth token exchange")
print(key)
}
}
print("AccessToken: \(accessToken!)")
} //End of receivedResults
let defaults = NSUserDefaults.standardUserDefaults()
defaults.setBool(true, forKey: "loadingOAuthToken")
}
}
答案 1 :(得分：1)
感谢Frederico的帮助。
我最终使用KeychainWrapper管理这种方式（管理敏感信息的钥匙串非常有用）。
如果有任何评论，请告诉我：
@IBAction func loginButtonTapped(sender: UIButton) {
self.emailTextField.resignFirstResponder()
self.passwordTextField.resignFirstResponder()
if (self.emailTextField.text == "" || self.passwordTextField.text == "") {
let alertView = UIAlertController(title: "Login failed",
message: "Wrong username or password." as String, preferredStyle:.Alert)
let okAction = UIAlertAction(title: "Try Again!", style: .Default, handler: nil)
alertView.addAction(okAction)
self.presentViewController(alertView, animated: true, completion: nil)
return
}
// Check if the user entered an email
if let actualUsername = self.emailTextField.text {
// Check if the user entered a password
if let actualPassword = self.passwordTextField.text {
// Build the body message to request the token to the web app
self.bodyStr = "grant_type=password&client_id=f3d259ddd3ed8ff3843839b&client_secret=4c7f6f8fa93d59c45502c0ae8c4a95b&username=" + actualUsername + "&password=" + actualPassword
// Setup the request
let myURL = NSURL(string: "http://test.com/oauth/access_token")!
let request = NSMutableURLRequest(URL: myURL)
request.HTTPMethod = "POST"
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
request.HTTPBody = bodyStr.dataUsingEncoding(NSUTF8StringEncoding)!
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
(data, response, error) -> Void in
if let unwrappedData = data {
do {
// Convert the Json object to an array of dictionaries
let tokenDictionary:NSDictionary = try NSJSONSerialization.JSONObjectWithData(unwrappedData, options: NSJSONReadingOptions.MutableContainers) as! NSDictionary
// Get the token
let token:String = tokenDictionary["access_token"] as! String
// Keep record of the token
let saveToken:Bool = KeychainWrapper.setString(token, forKey: "access_token")
// Dismiss login view and go to the home view controller
self.dismissViewControllerAnimated(true, completion: nil)
}
catch {
// Wrong credentials
// Reset the text fields
self.emailTextField.text = ""
self.passwordTextField.text = ""
// Setup the alert
let alertView = UIAlertController(title: "Login failed",
message: "Wrong username or password." as String, preferredStyle:.Alert)
let okAction = UIAlertAction(title: "Try Again!", style: .Default, handler: nil)
alertView.addAction(okAction)
self.presentViewController(alertView, animated: true, completion: nil)
return
}
}
}
task.resume()
}
}
}