Question

我需要为function descramble()制作动画。因此，它会更改第一个字符，然后在下一个字符上移动，依此类推。我尝试过使用setTimeout()，但这只会延迟函数的启动。我只需要通过信函为ROT13转换字母设置动画。

我正在使用slice()删除字符串的第一个元素，用ROT13替换它，然后用新字母和整个字符串替换字符串。我无法找到只删除段落第一个字母的方法。您可以单击jsfiddle中的第三个段落以查看转换。

$("#last-second-inside p:nth-child(3)").one('click', function() {
  $(this).css('cursor', 'default');
  var str = "Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.";
  var strArr = str.split('');
  var decodedArr = [];
  var increaseNum = -1;
  descramble();

  function descramble() {
    strArr.map(function(num) {
      increaseNum++;
      var currentLetter = num.charCodeAt();
      if (currentLetter >= 65 && currentLetter <= 90 || currentLetter >= 97 && currentLetter <= 122) {
        if (currentLetter >= 78 && currentLetter <= 90 || currentLetter >= 110 && currentLetter >= 97) {
          decodedArr.push(String.fromCharCode(currentLetter - 13));
        } else {
          decodedArr.push(String.fromCharCode(currentLetter + 13));
        }
      } else {
        decodedArr.push(num);
      }
      var sliced = str.slice(increaseNum + 1, str.length - 1);
      $("#last-second-inside p:nth-child(3)").text(decodedArr.join('') + sliced);
    })
  }
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="last-second-inside">
  <p>You probably now understand that how binary works and how simple it is.</p>
  <p>Now, I need you to think about that how you might display 8 in binary. After giving it a shot, you can click on the next paragraph to descramble it.</p>
  <p>Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.</p>
</div>

Answer 1

不要使用map()，而是descramble()根据increaseNum的值，一次只能处理一个字母。

运行descramble()后，使用setTimeout()在适当的时间间隔后再次调用它：

$("#last-second-inside p:nth-child(3)").one('click', function() {
  $(this).css('cursor', 'default');
  var str = "Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.";
  var strArr = str.split('');
  var decodedArr = [];
  var increaseNum = 0;  // changed from -1
  descramble();

  function descramble() {
    var num = str[increaseNum++],
        currentLetter = num.charCodeAt();

    if (currentLetter >= 65 && currentLetter <= 90 || currentLetter >= 97 && currentLetter <= 122) {
      if (currentLetter >= 78 && currentLetter <= 90 || currentLetter >= 110 && currentLetter >= 97) {
        decodedArr.push(String.fromCharCode(currentLetter - 13));
      } else {
        decodedArr.push(String.fromCharCode(currentLetter + 13));
      }
    } else {
      decodedArr.push(num);
    }
    var sliced = str.slice(increaseNum + 1, str.length - 1);
    $("#last-second-inside p:nth-child(3)").text(decodedArr.join('') + sliced);
    if(increaseNum < str.length) {
      setTimeout(descramble, 10);
    }
  }
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="last-second-inside">
  <p>You probably now understand that how binary works and how simple it is.</p>
  <p>Now, I need you to think about that how you might display 8 in binary. After giving it a shot, you can click on the next paragraph to descramble it.</p>
  <p>Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.</p>
</div>

Answer 2

尝试使用.queue()

＆＃13;

$("#last-second-inside p:nth-child(3)").one('click', function() {
  $(this).css('cursor', 'default');
  var str = "Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.";
  var strArr = str.split('');
  var decodedArr = [];
  var increaseNum = -1;
  descramble();

  function descramble() {
    $({}).queue("descramble", strArr.map(function(num) {
      return function(next) {
        increaseNum++;
        var currentLetter = num.charCodeAt();
        if (currentLetter >= 65 && currentLetter <= 90 || currentLetter >= 97 && currentLetter <= 122) {
          if (currentLetter >= 78 && currentLetter <= 90 || currentLetter >= 110 && currentLetter >= 97) {
            decodedArr.push(String.fromCharCode(currentLetter - 13));
          } else {
            decodedArr.push(String.fromCharCode(currentLetter + 13));
          }
        } else {
          decodedArr.push(num);
        }
        var sliced = str.slice(increaseNum + 1, str.length - 1);
        $("#last-second-inside p:nth-child(3)").text(decodedArr.join('') + sliced);
        // set duration of `setTimeout` here
        setTimeout(next, 100)
      };
    })).dequeue("descramble")
  }
})

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="last-second-inside">
  <p>You probably now understand that how binary works and how simple it is.</p>
  <p>Now, I need you to think about that how you might display 8 in binary. After giving it a shot, you can click on the next paragraph to descramble it.</p>
  <p>Vg'f fvzcyr lbh jvyy whfg nqq nabgure pbyhza nsgre sbhe'f cynpr naq gung pbyhza jvyy unir gur cynpr inyhr bs rvtug'f.</p>
</div>

＆＃13;

Answer 3

使用setInterval，而不是setTimeout。 setTimeout只运行一次（在计时器到期后）。 setInterval将以您设置的间隔继续射击，直到您逃离循环。

您可以将setTimeout视为单个触发倒数计时器。 setInterval可以被视为以您设置的间隔触发的循环。

Answer 4

我相信你将不得不手动进行映射。你不能在像每个，map等迭代器中使用setTimeout或setInterval并得到你期望的结果，因为setTimeout是非阻塞的，所以它立即返回。你必须调用一个自动调用的函数，它一次转换1个字母，当你到达字符串的末尾时就会破坏逻辑，如下所示： How do I add a delay in a JavaScript loop?

如何为此功能设置动画？

4 个答案: