我有两张很棒的桌子,我想用它作为更大的第三张桌子的基础!
输出取决于日期间隔,如09/01/2010 - 09/03/2010
来自表A <的输出示例 - - (已分配测试人员)
Date Country Allocated testers
09/01/2010 Nigeria 0
09/02/2010 Nigeria 1
09/03/2010 Nigeria 134
09/01/2010 China 2
09/02/2010 China 0
09/03/2010 China 14
09/01/2010 Chile 3
09/02/2010 Chile 4
09/03/2010 Chile 0
*************
来自表B 的输出示例 - - (缺席测试人员)
Date Country Absent testers
09/01/2010 Nigeria 0
09/02/2010 Nigeria 7
09/03/2010 Nigeria 0
09/01/2010 China 2
09/02/2010 China 0
09/03/2010 China 0
09/01/2010 Chile 1
09/02/2010 Chile 0
09/03/2010 Chile 0
*************
表C中的WANTED输出示例(已分配和未分配的测试人员)
Date Country Allocated testers Absent testers
09/01/2010 Nigeria 0 0
09/02/2010 Nigeria 1 7
09/03/2010 Nigeria 134 0
09/01/2010 China 2 2
09/02/2010 China 0 0
09/03/2010 China 14 0
09/01/2010 Chile 3 2
09/02/2010 Chile 4 0
09/03/2010 Chile 0 0
这里有一些SQL代码生成上面显示的输出......(是的,它们可以工作)
表A
WITH Calendar AS (SELECT CAST(@StartDate AS datetime) AS Date
UNION ALL
SELECT DATEADD(d, 1, Date) AS Expr1
FROM Calendar AS Calendar_1
WHERE (DATEADD(d, 1, Date) < @EndDate))
SELECT C.Date, C2.Country, COALESCE (SUM(R.[Amount of people per day needed]), 0) AS [Allocated testers]
FROM Calendar AS C CROSS JOIN
Country AS C2 LEFT OUTER JOIN
Requests AS R ON C.Date BETWEEN R.[Start date] AND R.[End date] AND R.CountryID = C2.CountryID
GROUP BY C.Date, C2.Country OPTION (MAXRECURSION 0)
表B
WITH Calendar AS (SELECT CAST(@StartDate AS datetime) AS Date
UNION ALL
SELECT DATEADD(d, 1, Date) AS Expr1
FROM Calendar AS Calendar_1
WHERE (DATEADD(d, 1, Date) < @EndDate))
SELECT C.Date, C2.Country, COALESCE (COUNT(PA.PeopleID), 0) AS [Absent testers]
FROM Calendar AS C CROSS JOIN
Country AS C2 INNER JOIN
Roles AS R INNER JOIN
People AS P ON R.RolesID = P.RolesID ON C2.CountryID = P.CountryID LEFT OUTER JOIN
PeoplesAbsence AS PA ON C.Date BETWEEN PA.StartDate AND PA.EndDate AND P.PeopleID = PA.PeopleID
WHERE (R.Role = 'Tester')
GROUP BY C.Date, C2.Country OPTION (MAXRECURSION 0)
表C 是我需要帮助创建的: - )
注意:我想看一些示例代码,开始使用!
另请注意:我不想用SQL Server中的Views解决这个问题,因为它无法工作...... - 我需要3:rd表; - )
已解决!从 tdammers 获得解决方案(谢谢!),这就是实施时的样子:
WITH Calendar AS (SELECT CAST(@StartDate AS datetime) AS Date
UNION ALL
SELECT
DATEADD(d, 1, Date) AS Expr1
FROM
Calendar AS Calendar_1
WHERE
(DATEADD(d, 1, Date) < @EndDate))
SELECT a.Date, a.Country, a.[Allocated testers], b.[Absent testers] FROM ( SELECT
C.Date, C2.Country, COALESCE (SUM(R.[Amount of people per day needed]), 0) AS [Allocated testers]
FROM
Calendar AS C
CROSS JOIN
Country AS C2
LEFT OUTER JOIN
Requests AS R
ON
C.Date BETWEEN R.[Start date] AND R.[End date] AND R.CountryID = C2.CountryID
GROUP BY
C.Date, C2.Country ) as a LEFT OUTER JOIN ( SELECT C.Date, C2.Country, COALESCE (COUNT(PA.PeopleID), 0) AS [Absent testers]
FROM Calendar AS C CROSS JOIN
Country AS C2 INNER JOIN
Roles AS R INNER JOIN
People AS P ON R.RolesID = P.RolesID ON C2.CountryID = P.CountryID LEFT OUTER JOIN
PeoplesAbsence AS PA ON C.Date BETWEEN PA.StartDate AND PA.EndDate AND P.PeopleID = PA.PeopleID
WHERE (R.Role = 'Tester')
GROUP BY C.Date, C2.Country ) as b ON a.date = b.date AND a.country = b.country
答案 0 :(得分:2)
表C不应该是表格,而是视图。