Question

我试图使用google api进行购物（商家）并且我遇到了这个问题。

我对php不太熟悉，但对我来说代码似乎很好，我想做的就是尝试从我的商店中取出商品。我按照谷歌的建议步骤在开发者控制台中设置了客户端ID和客户端密码，但仍然在登录后我收到了错误。

这里的代码我使用：

<?php

/*
 * Uses google API to make an authorized request trough a google dev console project.
 */

require_once __DIR__ . '/../../google-api-php-client-master/vendor/autoload.php';
//require_once 'Google/Client.php';
//require_once 'Google/Service/ShoppingContent.php';
require_once '../Config.php';

$redirect_uri = $actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; //this is used during the auth process
//$merchantId = $_POST['merchantId'];
$merchantId = Config::MERCHANT_ID;
$service;

$client = Config::getGoogleClient();

$client->setRedirectUri($redirect_uri);
doOAuth($client);
echo "TOKEN : " + $client->getAccessToken() . " " . $_SESSION['oauth_access_token'];
//after authentication we can create a service object
$service = new Google_Service_ShoppingContent($client);

$products = $service->products->listProducts($merchantId);
$parameters = array();
while (!empty($products->getResources())) {
    foreach ($products->getResources() as $product) {
        printProduct($product);
    }
    if (!empty($products->getNextPageToken())) {
        break;
    }
    $parameters['pageToken'] = $products->nextPageToken;
    $products = $service->products->listProducts($merchantId, $parameters);
}

printf("\nEnd");

////////////////////////
//$_SESSION['oauth_access_token'] = null;
function doOAuth(&$client) {
    if (isset($_SESSION['oauth_access_token'])) {
        $client->setAccessToken($_SESSION['oauth_access_token']);
    } elseif (isset($_GET['code'])) {
//        $client->setAccessType("offline"); //IMPORTANT
        $token = $client->authenticate($_GET['code']);
        $_SESSION['oauth_access_token'] = $token;
    } else {
        header('Location: ' . $client->createAuthUrl());
        exit;
    }
}

function printProduct($product) {
    printf("%s %s\n", $product->getId(), $product->getTitle());
}

我收到以下错误：

0阵列致命错误：未捕获的异常＆＃39; Google_Service_Exception＆＃39; 消息＆＃39; {＆＃34;错误＆＃34;：{＆＃34;错误＆＃34;：[{＆＃34;域＆＃34;：＆＃34;全球＆＃34;，＆＃34;原因＆＃34 ;: ＆＃34;必需＆＃34;，＆＃34;消息＆＃34;：＆＃34;需要登录＆＃34;，＆＃34; locationType＆＃34;：＆＃34;标题＆＃34;，＆＃34; location＆＃34;：＆＃34;授权＆＃34; }，＆＃34;代码＆＃34;：401，＆＃34;消息＆＃34;：＆＃34;登录所需＆＃34; }＆＃39;在C：\ Program Files（x86）\ Apache Software中基金会\ Apache24 \ htdocs中\谷歌的API的PHP客户端主机的\ src \谷歌\ HTTP \ REST.php：123 堆栈跟踪：＃0 C：\ Program Files（x86）\ Apache Software 基金会\ Apache24 \ htdocs中\谷歌API的PHP客户端主机的\ src \谷歌\ HTTP \ REST.php（82）： Google_Http_REST :: decodeHttpResponse（对象（GuzzleHttp \ PSR7 \响应），对象（GuzzleHttp \ Psr7 \ Request），＆＃39; Google_Service _...＆＃39;）＃1 [内部功能]：Google_Http_REST :: doExecute（对象（GuzzleHttp \ Client），对象（GuzzleHttp \ Psr7 \ Request），＆＃39; Google_Service _...＆＃39;）＃2 C：\ Program 文件（x86）\ Apache软件基金会\ Apache24 \ htdocs中\谷歌的API的PHP客户端主机的\ src \谷歌\工作\ Runner.php（181）： call_user_func_array（Array，Array）＃3 C：\ Program Files（x86）\ Apac in C：\ Program Files（x86）\ Apache Software 基金会\ Apache24 \ htdocs中\谷歌的API的PHP客户端主机的\ src \谷歌\ HTTP \ REST.php 在第123行

感谢您的帮助

编辑：进一步的信息我能够在$ token对象

中检测到这个错误

[error] =＆gt; redirect_uri_mismatch [error_description] =＆gt;错误的要求

块引用

Answer 1

/**
 * IMPORTANT: this url is used during both two phases of OAuth.
 * If a mistmatch of the redirect uri occours during the two phases, the login
 * fails. Must ignore the code (get) parameter in the second phase.
**/
$redirect_uri = "http://localhost/gshop/action/list.php";

旧的uri是动态的，带有代码参数

php 401中的Google API OAuth需要登录

1 个答案: