Question

我有以下MySQL表Test_Results

| ID | Test_ID | Device_OS| Status | Date     | Device_ID |
| 1  | 1       | Android  | passed | 2015/10  | 1         |
| 2  | 1       | Android  | failed | 2015/10  | 1         |
| 3  | 15      | iOS      | failed | 2015/11  | 2         |
| 4  | 20      | Android  | passed | 2015/11  | 1         |
| 5  | 27      | Android  | failed | 2015/11  | 1         |
| 6  | 10      | iOS      | failed | 2015/12  | 2         |
| 7  | 5       | Android  | passed | 2015/12  | 1         |

我需要在ID = 1的设备上选择失败的测试，但是在ID = 2的设备上传递。

所以我需要根据Device_ID比较值，请你指点一下在互联网上搜索的内容。

Answer 1

如果您希望满足这两个条件，请尝试以下方法：

SELECT Test_ID
FROM Test_Results
WHERE Test_ID IN (SELECT Test_ID FROM Test_Results WHERE Device_ID = 1 AND Status LIKE 'failed')
AND Device_ID = 2 AND Status LIKE 'passed'

Answer 2

select Test_ID, COUNT(Test_ID) as TEST_COUNT from Test_Results 
where (Status='failed' AND Device_ID = 1) OR (Status='passed' AND Device_ID = 2)
group by Test_ID
Having TEST_COUNT>1

Answer 3

以安全的方式制作....

            SELECT * 
            FROM Test_Results
            WHERE (`Device_ID` = 1 AND `Status` = 'passed') 
                  OR
                  (`Device_ID` = 2 AND `Status` = 'failed');

希望能完美地运作......

MySQl：比较值的地方

3 个答案: