Question

以下是我调用__init__类Game_Events的代码：

class Game_Events(object):
    def __init__(self, DoSetup):
        if DoSetup == "yes":
            print "Done"

GE = Game_Events()
GE.__init__("no")

但是当我运行代码时，我得到了：

TypeError: __init__() takes exactly 2 arguments (1 given)

我该如何解决这个问题？

Answer 1

Game_Events() # calls Game_Events.__init__(newly_created_instance)被称为，，您不能直接调用它。在创建实例时调用它：

'no'

因为你没有传递给那个电话的参数，所以事情就会破裂。将GE = Game_Events('no') # calls Game_Events.__init__(newly_created_instance, 'no')传递给该电话：

sudo -s  // use as admin

#public key
wget -O - http://packages.elasticsearch.org/GPG-KEY-elasticsearch | apt-key add -

# edit /etc/apt/sources.list and add
deb http://packages.elasticsearch.org/elasticsearch/1.0/debian stable main
deb http://packages.elasticsearch.org/logstash/1.3/debian stable main

sudo apt-get update
sudo apt-get install elasticsearch

Answer 2

仅在为该类创建实例时调用

init 函数。

试试这个：

class Game_Events(object):
    def __init__(self, DoSetup):
        if DoSetup == "yes":
            print "Done"

GE = Game_Events("no")

GE = Game_Events("yes") # output will be yes

无法调用Python函数

2 个答案: