Question

 function put_SwVersion_MENAME()
{
    output=$(expect -c '
        log_user 0
        match_max 2000
        spawn ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null username@IP
        expect "*?Password:*"
        send "dummmy\r"
        expect "*#"
        send "cat /storage/system/abcd.txt\r"
        expect "cat /torage/system/abcd.txt\n"
        puts '"\$expect_out(buffer)"'
    ')
        echo $output
        return $TRUE
    }

    put_SwVersion_MENAME

输出值包含提示而不是发送输出我如何解析以获得正确的CAT值？

Answer 1

应该正确提示。由于命令和模式都相同，因此它会导致匹配我们自己发送的命令。（即cat /storage/system/abcd.txt\r）。

相反，接下来是匹配提示的通用方法，

set prompt "\r\n(.*?)(#|%|>|\\\$) $"

在这里，我们用反斜杠转义了字面的美元符号，最后一个美元用于行尾的正则表达式。

#!/bin/bash
function put_SwVersion_MENAME() {
        output=$(expect -c '
        log_user 0
        set prompt "\r\n(.*?)(#|%|>|\\\$) $"
        spawn ssh dinesh@xxx.xx.xx.xxx
        expect "password"
        send "welcome123\r"
        expect -re $prompt
        send "cat /storage/system/abcd.txt\r"
        expect -re $prompt
        puts "$expect_out(1,string)"
        ')
        echo "===>$output<=="
}
put_SwVersion_MENAME

Answer 2

我也面临类似的问题，并且在添加\ r之后得到了解决并且期望介于两者之间。这可以帮到你。请试试。

    expect "password"
    send "welcome123\r"
    expect -re $prompt
    send "cat /storage/system/abcd.txt\r"
    expect -re $prompt
    send "\r"
    expect -re $prompt
    puts "$expect_out(buffer)"

解析expect_out缓冲区以忽略提示并获取send命令所需的值

2 个答案: