Question

我使用Java Executors.newWorkStealingPool();并行运行多个命令。由于其中一些任务预计会超时，我为它们添加了2秒的超时。

ProcessBuilder pb = new ProcessBuilder(cmd.split(" "));
Process p = null;
StringBuilder result = new StringBuilder();
try {
    p = pb.start();
    p.waitFor(2000, TimeUnit.MILLISECONDS);
    BufferedReader errreader = 
    new BufferedReader(new InputStreamReader(p.getErrorStream()));
    BufferedReader outreader = new BufferedReader(new InputStreamReader(p.getInputStream()));
    String line = "";           
    while ((line = outreader.readLine())!= null) 
    result.append(line + "\n");
    while ((line = errreader.readLine())!= null) 
        result.append(line + "\n");
    outreader.close();
    errreader.close();
    } catch (InterruptedException e) {
        result.append("INTERRUPTED");
    } catch (IOException e) {
        e.printStackTrace();
        System.exit(-1);
    }
    finally {
        p.destroy();
    }
    ....
    return b; // b is boolean

提交任务看起来像这样

List<ImmutablePair> curJobs = new ArrayList<ImmutablePair>();
for (int i = 0; i <  allMutants.size(); i++) {
    String mutant = allMutants.get(i);
    t = executor.submit(new mutTask(mutant));
    ImmutablePair pair = new ImmutablePair(mutant, t);
    curJobs.add(pair);
    }

最后。我在以下循环中收集结果。

// data collection loop
for (int i = 0; i< curJobs.size(); i++) {
        ImmutablePair p = curJobs.get(i);
        String m= (String) p.getLeft();
    System.out.println(m);
        t = (Future<Boolean>) p.getRight();
    try {
        boolean res;
        try {
            res = t.get(2000L, TimeUnit.MILLISECONDS);

        } catch (TimeoutException e) {
            res = true;
        }
        finally {
            t.cancel(true);
        }}

问题在于，超时似乎不会终止程序中定义的某些命令或进程。几分钟后，数据收集循环变得非常缓慢。 ps的结果显示一些运行远远超过指定超时并保持CPU忙的作业。我的配置是CentOS上的JDK8。

Answer 1

正如@MadProgrammer所指出的那样，问题是在进程终止时读出/错误缓冲区。要解决此问题，您需要检查p.waitFor(2000, TimeUnit.MILLISECONDS);

的输出

    try {
        p = pb.start();
        boolean timeout = !p.waitFor(2000, TimeUnit.MILLISECONDS);
        if (!timeout){
            BufferedReader errreader =
                     new BufferedReader(new InputStreamReader(p.getErrorStream()));
            BufferedReader outreader =
                     new BufferedReader(new InputStreamReader(p.getInputStream()));

            String line = "";
            while ((line = outreader.readLine())!= null)
                result.append(line + "\n");
            while ((line = errreader.readLine())!= null)
                    result.append(line + "\n");
            outreader.close();
            errreader.close();
        }

    } catch ...

流程不会终止

1 个答案: