我有一个带菜单的QToolButton。单击QToolButton时,将显示菜单。默认行为是,当从菜单中单击操作时,菜单将消失。我怎样才能使菜单保持打开状态直到用户点击其他地方?
以下是显示行为的最小代码:
from PyQt4 import QtGui, QtCore
import sys, os
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
toolButton = QtGui.QToolButton()
toolButton.setText('Select')
toolMenu = QtGui.QMenu()
for i in range(3):
action = toolMenu.addAction(str(i))
action.setCheckable(True)
toolButton.setMenu(toolMenu)
toolButton.setPopupMode(QtGui.QToolButton.InstantPopup)
toolButton.show()
sys.exit(app.exec_())
答案 0 :(得分:1)
从this c ++回答:
无耻地移植此代码from PyQt4 import QtGui, QtCore
import sys, os
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
toolButton = QtGui.QToolButton()
toolButton.setText('Select')
toolMenu = QtGui.QMenu()
for i in range(3):
checkBox = QtGui.QCheckBox(str(i), toolMenu)
checkableAction = QtGui.QWidgetAction(toolMenu)
checkableAction.setDefaultWidget(checkBox)
toolMenu.addAction(checkableAction)
toolButton.setMenu(toolMenu)
toolButton.setPopupMode(QtGui.QToolButton.InstantPopup)
toolButton.show()
sys.exit(app.exec_())
答案 1 :(得分:0)
我设法找到的最简单的解决方案是添加Thread
:
static
答案 2 :(得分:0)
我正在寻找完全相同的东西,并使用了three_pineapples的代码,但我无法按照我想要的方式连接它。我以为我会分享我的解决方案以防其他人发现它有用。 按钮功能非常相似,但我的代码包含我将复选框连接到函数的解决方案。此外,由于它们存储在列表中,因此可以单独或循环连接它们,如果这样更容易的话。
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys, os
##### main window class #####
class main_window(QMainWindow):
def __init__(self):
super(main_window, self).__init__()
self.resize(300, 200)
wdgMain = QWidget()
self.setCentralWidget(wdgMain)
layMain = QGridLayout(wdgMain)
wdgMain.setLayout(layMain)
## checkable tool button ##
tlbToolButton1 = QToolButtonChx("Check Me Out!")
layMain.addWidget(tlbToolButton1, 0, 0)
tlbToolButton1.addItems(["Item" + str(n) for n in range(8)])
## connect tool button checkboxes ##
for i in range(tlbToolButton1.length()):
tlbToolButton1.index(i).stateChanged.connect(self.checkbox_tester)
def checkbox_tester(self, choice):
objSender = self.sender()
strObjectName = objSender.objectName()
print "Action Checker::", strObjectName, ":", choice
##### end of main window class #####
##### checkable tool button class #####
class QToolButtonChx(QToolButton):
def __init__(self, strText=""):
super(QToolButtonChx, self).__init__()
self.setText(strText)
tlbMenu = QMenu(self)
self.setMenu(tlbMenu)
self.setPopupMode(QToolButton.MenuButtonPopup)
self.lstchxItems = []
def addItem(self, strItem):
self.lstchxItems.append(QCheckBox(strItem, self.menu()))
actCheckItem = QWidgetAction(self.menu())
actCheckItem.setDefaultWidget(self.lstchxItems[-1])
self.lstchxItems[-1].setObjectName('chx' + strItem)
self.menu().addAction(actCheckItem)
def addItems(self, lstItems):
for strItem in lstItems:
self.lstchxItems.append(QCheckBox(strItem, self.menu()))
actCheckItem = QWidgetAction(self.menu())
actCheckItem.setDefaultWidget(self.lstchxItems[-1])
self.lstchxItems[-1].setObjectName('chx' + strItem)
self.menu().addAction(actCheckItem)
def index(self, intIndex):
return self.lstchxItems[intIndex]
def length(self):
return len(self.lstchxItems)
##### end of checkable tool button class #####
if __name__ == '__main__':
app = QApplication(sys.argv)
winMain = QMainWindow()
gui = main_window()
gui.show()
sys.exit(app.exec_())
答案 3 :(得分:0)
我根据@three_pineapples的回答制作了一个PyQt5版本,并解决了@Space Hornet试图解决的问题-获取复选框的状态。
请注意,取决于小部件来激活操作,例如 通过重新实现鼠标事件处理程序并调用QAction :: trigger()。
因此,我认为有人需要将复选框的stateChanged
信号连接到操作的trigger
方法。
我还向操作添加了一个文本,因此action.text()
的文本标签与复选框相同。也许不是必需的。
完整的代码如下:
import sys
from PyQt5 import QtWidgets
from PyQt5.QtCore import pyqtSlot
@pyqtSlot(QtWidgets.QAction)
def menuTriggered(action):
print('state change=',action.text())
return
@pyqtSlot(QtWidgets.QMenu)
def buttonTriggered(menu):
actions=menu.findChildren(QtWidgets.QWidgetAction)
for actii in actions:
wii=actii.defaultWidget()
stateii=wii.isChecked()
print('action', actii.text(), 'is checked:',stateii)
return
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
toolButton = QtWidgets.QToolButton()
toolButton.setText('Select')
toolMenu = QtWidgets.QMenu()
for i in range(3):
checkBox = QtWidgets.QCheckBox(str(i), toolMenu)
checkableAction = QtWidgets.QWidgetAction(toolMenu)
checkableAction.setDefaultWidget(checkBox)
# Add a text to action, for easier handling in slot
checkableAction.setText(str(i))
# Connect the checkbox's stateChanged to QAction.trigger
checkBox.stateChanged.connect(checkableAction.trigger)
toolMenu.addAction(checkableAction)
toolMenu.triggered.connect(menuTriggered)
toolButton.setMenu(toolMenu)
toolButton.setPopupMode(QtWidgets.QToolButton.MenuButtonPopup)
# NOTE that toolButton.clicked work, toolButton.triggered not
toolButton.clicked.connect(lambda: buttonTriggered(toolMenu))
toolButton.show()
sys.exit(app.exec_())