Question

基本上，我正在创建一个用于转换电话号码的程序字母，只是简单的数字。我设法做到了这一点，但是，如果您输入数字，它们将被删除，并且只能转换信件被退回。

例如，如果您输入1800BUYNOW，而不是返回1800289669，它只返回289669。

任何帮助？

#phone number converter
#v0.8
#this will convert phone numbers with letters in, into just phone numbers
#i.e. 1800BUYNOW should output as 1800289669

import time
import string

dicti = []

#######################################################################

def translate():
    print('Welcome to the telephone unconfuzzler!')
    num = input('''Type the number you which to deconfuzzle.
''')
    for char in (num):
        if char in ['A','B','C']:
            dicti.append(2)
        if char in ['D','E','F']:
            dicti.append(3)
        if char in ['G','H','I']:
            dicti.append(4)
        if char in ['J','K','L']:
            dicti.append(5)
        if char in ['M','N','O']:
            dicti.append(6)
        if char in ['P','Q','R','S']:
            dicti.append(7)
        if char in ['T','U','V']:
            dicti.append(8)
        if char in ['W','X','Y','Z']:
            dicti.append(9)
    finish()

#######################################################################

def finish():
     time.sleep(0.5)
     print('''Converting
...''')
     time.sleep(1)
     print('''Here is your deconfuzzled number:''')
     print (*dicti, sep='')
     end()

#######################################################################

def end():
    conta = input('Would you like to convert another number?')
    if conta in ['y', 'Y', 'yes', 'Yes', 'YES']:
        translate()
    elif conta in ['n', 'N', 'no', 'No', 'NO']:
        conta2 = input('Are you sure you would like to quit?')
        if conta2 in ['y', 'Y', 'yes', 'Yes', 'YES']:
            exit()
        elif conta2 in ['n', 'N', 'no', 'No', 'NO']:
            end()


#######################################################################

translate()

Answer 1

只需替换

   if char in ['A','B','C']:

通过

   if char in ['A','B','C','1']:

等等。

实际上你最后应该有一个报告未知字符的其他内容并用elif替换if。

将整数存储在输入中，分别存储在字符

1 个答案: