使用 - spring-social 1.1.4 - spring-social-twitter 1.1.2 - spring-mvc-4.2 - 关于tomcat 7
下面是我的MVC应用程序的tomcat配置,包括twitter设置和usersConnectionRepository。
这对于登录的MVC用户来说都很好。
当我想允许客户端从非MVC认证用户可用的公共链接发送推文时,问题就出现了。 (#{request.userPrincipal.name}将为null)
我看了很多例子。 大多数示例使用旧的1.0.0 spring-social。 我注意到spring-social- twitter 的新1.1.2版本没有零参数Twitter()构造函数,在某些示例中,它显示为没有connectionRepository的工作方式。
我正在寻找一种配置或编码选项的方法,以允许用户登录我的应用程序和匿名用户使用我网站上的某些选项。
在下面的配置中,重定向到connect / twitter的匿名用户将导致获取connetionRepository时出现问题。 usersConnectionRepository必须有一个"#{request.userPrincipal.name}"因为我的connectController依赖于此。
我想也许我需要一个自定义连接控制器...... 必须有一个正确的方法来解决这个问题。
欢迎任何建议。
我的web.xml
<listener>
<listener-class>
org.springframework.web.util.Log4jConfigListener
</listener-class>
</listener>
<display-name>Central Portal</display-name>
<context-param>
<param-name>spring.profiles.active</param-name>
<param-value>dev</param-value>
</context-param>
<context-param>
<param-name>spring.profiles.default</param-name>
<param-value>dev</param-value>
</context-param>
<context-param>
<param-name>spring.liveBeansView.mbeanDomain</param-name>
<param-value>dev</param-value>
</context-param>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<error-page>
<error-code>500</error-code>
<location>/WEB-INF//pages/error.jsp</location>
</error-page>
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/pages/error.jsp</location>
</error-page>
<error-page>
<location>/WEB-INF/pages/error.jsp</location>
</error-page>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-security.xml,
/WEB-INF/spring-database.xml
</param-value>
</context-param>
<!-- Enable POST -->
<filter>
<filter-name>hiddenHttpMethodFilter</filter-name>
<filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>hiddenHttpMethodFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Concurrency listener -->
<listener>
<listener-class>
org.springframework.security.web.session.HttpSessionEventPublisher
</listener-class>
</listener>
MVC-调度-servlet.xml中
<context:component-scan base-package="org.schoolit.usermanager.config" />
<!-- component-scan / controllers -->
<context:component-scan base-package="org.schoolit.webapplication.*" />
<context:component-scan base-package="org.schoolit.spring.social.*"/>
<!-- property-placeholder's -->
<context:property-placeholder location="classpath:oauth.properties"/>
<!-- resource mapping -->
<mvc:resources mapping="/gen/**" location="/WEB-INF/gen/" cache-period="31556926"/>
<mvc:resources mapping="/resources/**" location="/WEB-INF/resources/" cache-period="31556926"/>
<!-- JSP ViewResolver -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<!-- twitter stuff start -->
<bean id="handlerExceptionResolver" class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver">
<property name="exceptionMappings">
<props>
<prop key="Exception">error</prop>
</props>
</property>
</bean>
<bean id="twitterTemplate"
class="org.springframework.social.twitter.api.impl.TwitterTemplate">
<constructor-arg value="${twitter.oauth.consumerKey}"/>
<constructor-arg value="${twitter.oauth.consumerSecret}"/>
<!--<constructor-arg value="${twitter.oauth.accessToken}"/>
<constructor-arg value="${twitter.oauth.accessTokenSecret}"/> -->
</bean>
<bean id="connectionFactoryLocator" class="org.springframework.social.connect.support.ConnectionFactoryRegistry">
<property name="connectionFactories">
<list>
<bean class="org.springframework.social.twitter.connect.TwitterConnectionFactory">
<constructor-arg value="${twitter.oauth.consumerKey}" />
<constructor-arg value="${twitter.oauth.consumerSecret}" />
</bean>
</list>
</property>
</bean>
<bean id="connectionRepository" factory-method="createConnectionRepository" factory-bean="usersConnectionRepository" scope="request">
<constructor-arg value="#{request.userPrincipal.name}" />
<aop:scoped-proxy proxy-target-class="true" />
</bean>
<bean id="usersConnectionRepository"
class="org.springframework.social.connect.jdbc.JdbcUsersConnectionRepository">
<constructor-arg ref="dataSource" />
<constructor-arg ref="connectionFactoryLocator" />
<constructor-arg ref="textEncryptor" />
</bean>
<bean id="textEncryptor" class="org.springframework.security.crypto.encrypt.Encryptors"
factory-method="noOpText" />
<bean id="connectController" class="org.springframework.social.connect.web.ConnectController">
<constructor-arg ref="connectionFactoryLocator"/>
<constructor-arg ref="connectionRepository"/>
<property name="applicationUrl" value="http://localhost:8080/CentralPortal/" />
<property name="connectInterceptors">
<list>
<bean class="org.schoolit.spring.social.TweetAfterConnectInterceptor"/>
</list>
</property>
</bean>
弹簧database.xml
<!-- App's dataSource used by jdbcTemplate,jdbc-user-service and connectController -->
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/spring_me" />
<property name="username" value="root" />
<property name="password" value="<mypassword>" />
</bean>
<!-- jdbcTemplate used in usermanager bit only for now. -->
<bean id="jdbcTemplate" class="org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate">
<constructor-arg ref="dataSource" />
</bean>
spring-security.xml
<!-- enable use-expressions -->
<http auto-config="true" use-expressions="true">
<!-- Set up rolefilter's for requestmapping's -->
<intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />
<intercept-url pattern="/usermanager**" access="hasRole('ROLE_ADMIN')" />
<intercept-url pattern="/users**" access="hasRole('ROLE_ADMIN')" />
<!-- access denied page -->
<access-denied-handler error-page="/403" />
<!-- loginform-setup Spring Security -->
<form-login
login-page="/login"
default-target-url="/home"
login-processing-url="/j_spring_security_check"
authentication-failure-url="/login?error"
username-parameter="username"
password-parameter="password" />
<logout logout-success-url="/login?logout" />
<!-- enable csrf protection default is enabled from 4.0 spring
<csrf /> <csrf disabled="true"/> -->
<csrf request-matcher-ref="connect/*" disabled="true"/>
<!-- Prevent Clickjacking iframe's -->
<headers>
<frame-options policy="SAMEORIGIN"/>
</headers>
<!-- One login per username should be one set to 5 for testing-->
<session-management>
<concurrency-control max-sessions="1" error-if-maximum-exceeded="true" expired-url="/login?error" />
</session-management>
</http>
<!-- Select users and user_roles from database -->
<authentication-manager>
<authentication-provider>
<password-encoder ref="encoder" />
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query="select username,password, enabled from users where username=?"
authorities-by-username-query="select username, role from user_roles where username =? " />
</authentication-provider>
</authentication-manager>
<!-- encoder bean. Used for password encryption -->
<beans:bean id="encoder"
class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
<beans:constructor-arg name="strength" value="11" />
</beans:bean>
答案 0 :(得分:2)
我看到您配置了PhotoCol = new FS.Collection('propertyPhoto', {
stores: [
new FS.Store.FileSystem('original')
],
filter: {
allow: {
contentTypes: ['image/*']
}
}
});
PhotoCol.allow({
insert: function() {
return true;
},
update: function() {
return true;
},
remove: function() {
return true;
},
download: function() {
return true;
}
});
bean,如果您能够在应用程序中使用它,则无需执行任何其他操作。
使用twitterTemplate
代替TwitterTemplate
。
Twitter
实现TwitterTemplate
接口,因此所有方法都可用。
示例:
Twitter
使用//1. Search Twitter
SearchResults results = twitterTemplate.searchOperations().search("#WinterIsComing");
List<Tweet> tweets = results.getTweets();
int i =0;
for (Tweet tweet : tweets) {
System.out.println(tweet.getUser().getName() + " Tweeted : "+tweet.getText() + " from " + tweet.getUser().getLocation()
+ " @ " + tweet.getCreatedAt() + tweet.getUser().getLocation() );
}
//2. Search Place by GeoLocation
RestTemplate restTemplate = twitterTemplate.getRestTemplate();
GeoTemplate geoTemplate = new GeoTemplate(restTemplate, true, true);
List<Place> place = geoTemplate.search(37.423021, -122.083739);
for (Place p : place) {
System.out.println(p.getName() + " " + p.getCountry() + " "+p.getId());
}
//3. Get Twitter UserProfile
TwitterProfile userProfile = twitterTemplate.userOperations().getUserProfile();
System.out.println(userProfile.getName()+" has " +userProfile.getFriendsCount() + " friends");
,用户无需登录。希望这有帮助!